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Mathematics

1 answer:

matrenka [14]3 years ago

4 0

Huh, this is presented pretty interesting to me.

To start with, if you actually had no idea what the answer to this question was, you wouldn't pick B or C because x has to be close to 91°. In this particular quadrilateral, it's especially important that we focus on the fact, "x - 15." This means that x has to be higher initially to be subracted to equal 91, or the opposite angle.

In order to subtract to 91, the answer would have to be 106, or D. This is a hunch, but I have a suspicion that angle B and D are going to be the same, being that their on opposite sides of the figure.

Hope this helps! If you have further questions, let me know.

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'Ciumane ananen<br> 32.50t + 5 = 28.75t + 20

gtnhenbr [62]

Answer:

The answer is 0.25

Step-by-step explanation:

(1)we group like terms by subtracting 32.50 by 28.75

(2) we subtract 20 and 5 to give us a value of 15

(3)when we subtract 32.50 and 28.75 we get a value of 3.75

(4)so the equation will look like this 3.75t = 15

(5)we divide 3.75 we both the two equations

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3 years ago

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3 years ago

Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD

Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = $\sqrt{75+25}$ = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that $\frac{1}{2} * BF = \frac{1}{2} * 5 * \sqrt{75}$ and BF= $0.5\sqrt{75}$ . Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is $A= BF * \frac{AB+CD}{2} = 0.5 \sqrt{75} * \frac{5+10}{2} = 18.75 \sqrt{3} cm^{2}$

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