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elena55 [62]
3 years ago
7

The function rule T(m)=450-8m represents the amount of water T(m) (in liters) in a holding tank after being drained at a rate of

8L/min for m minutes. how much time has passed if there are 274 L of water in the tank
A. 18 min
B. 20 min
C. 22 min
D. 24 min

if you can please explain and work it out please
Mathematics
2 answers:
suter [353]3 years ago
7 0
Well they give you the equation and they want you to solve for time given that you know the amount of water in the tank.  They tell you T=274 and that

T=450-8m  so using the value T=274 in the equation to the left gives you:

274=450-8m  subtract 450 from both sides

-176=-8m  divide both sides by -8

22=m

So 22 minutes have passed when there is 274L remaining...
bija089 [108]3 years ago
4 0
22  sorry if I'm wrong
<span>---------------------------</span>
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Sarah wants to arrive at her friends wedding at 3:00 pm. The distance from Sarah’s house to the wedding is 85 miles. Based on us
Mrrafil [7]

Answer:

(A) 15 minutes

(B) 10 minutes

(C) 1 hour

(D) 1:35 pm

Step-by-step explanation:

<em>Question:</em>

Sarah wants to arrive at her friend’s wedding at 3:00 PM. The distance from Sarah’s house to the wedding is 85 miles. Based on usual traffic patterns, Sarah predicts she can drive the first 15 miles at 60 miles per hour, the next 5 miles at 30 miles per hour, and the remainder of the drive at 65 miles per hour.

(A) how many minutes will it take Sarah to drive the first 15 miles?

(B) how many minutes will it take Sarah to drive 5 miles?

(C) how many hours will it take Sarah to drive the rest of the trip?

(D) what time should Sarah leave her house? (Give your answer using standard hour:minute clock format.)

<em>Solution:</em>

Total distance = 85 miles

There are three segments of this trip, each one with its own speed.

<em>1) 15 miles at 60 mph</em>

<em>2) 5 miles at 30 mph</em>

Up to here, the distance is 15 miles + 5 miles = 20 miles.

The total distance is 85 miles, so the last segment of the trip is 85 miles - 20 miles = 65 miles.

<em>3) 65 miles at 65 mph</em>

The equation for speed is:

speed = distance/time

Now we solve it for time:

speed * time = distance

time = distance/speed

To find a time, divide the distance by the speed.

Part (A)

distance = 15 miles; speed = 60 mph; find time

time = distance/speed = 15 miles/60 mph = 0.25 hours

Since 1 hour = 60 minutes,

time = 0.25 hours * 60 minutes/hour = 15 minutes

Part (B)

distance = 5 miles; speed = 30 mph; find time

time = distance/speed = 5 miles/30 mph = 1/6 hour

Since 1 hour = 60 minutes,

times = 1/6 hour * 60 minutes/hour = 10 minutes

Part (C)

distance = 65 miles; speed = 65 mph; find time

time = distance/speed = 65 miles/65 mph = 1 hour

Part (D)

The driving times for the three segments are 15 minutes, 10 minutes, and 1 hour. The total driving time is

15 minutes + 10 minutes + 1 hour = 1 hour and 25 minutes

Now we subtract 1 hour 25 minutes from 3:00 pm.

3:00 pm is the same as 2:60 pm

2:60 pm - 1:25 = 1:35 pm

She needs to leave at 1:35 pm

5 0
3 years ago
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