OK, wonderful. It should be very comfortable in there, since it's so small and fits so easily.
The circle can be placed completely inside the rectangle, in positions where it touches one side, two sides, or no sides. It's too small to touch thee sides or four sides all at the same time.
Do you have some kind of question to ask regarding the situation ?
<em>Answer,</em>
<em><u>X = 3/4</u></em>
<em>Explanation,</em>
<u><em>Step 1: Simplify both sides of the equation.</em></u>
<em>3.25 + 0.5x + (1)(1)/3 + 5/6x = (5)(11)/12</em>
<em>3.25 + 0.5x + 1/3 + 5/6x = 55/12</em>
<em>(</em><em>0.5x + 5/6x</em><em>) + (</em><u><em>3.25 + 1/3</em></u><em>) = 55/12 (Combine Like Terms)</em>
<em>4/3x + 3.583333 = 55/12 </em>
<em>4/3x + 3.583333 = 55/12</em>
<u><em>Step 2: Subtract </em></u><u><em>3.583333</em></u><u><em> from both sides.</em></u>
<em>4/3x + 3.583333 − 3.583333 = 55/12 − 3.583333 </em>
<em>4/3x = 1</em>
<u><em>Step 3: Multiply both sides by </em></u><u><em>3/4.</em></u><u><em> </em></u>
<em>(3/4) * (4/3x) = (3/4) * (1)</em>
<em>x = 3/4</em>
Answer:
1. A 2. B
Step-by-step explanation:
Whatever happens to x must also happen to y.
For the first question, x is doubled, which means that the value of y is also doubled.
For the second question, if the value of x triples, then the value of y triples as well, which means that it would be multiplied by 3.
We can check to see if these two answers are true by inputting values into the equations.
For the first equation, let's use the example x = 2
y = 5(2)
y = 10
If the value if x doubled, it would become x = 4
y = 5(4)
y = 20
As you can see, when the value of x doubled from 2 to 4, the value of y also doubled from 10 to 20.
You can do something similar for the other equation.