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Pani-rosa [81]
3 years ago
14

Brainliest to whoever gets this correct , Describe the end behavior of the following function:

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

Answer:

graph starts high and ends high

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Is the fraction 1/15 a terminating or repeating decimal?
german
-A terminating decimal is a decimal that NEVER ends

1/15 = 0.666666666.....

Therefore, 1/15 is a terminating decimal.
3 0
3 years ago
HELP ASAP what is 9/10-5/10=
Fofino [41]

9/10 - 5/10

because the denominators are the same you keep it and just subtract the numerators

=4/10

This can be reduced to 2/5

6 0
3 years ago
Read 2 more answers
If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?
Keith_Richards [23]
\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}

so, the domain is all real numbers EXCEPT that one.
4 0
3 years ago
The equation of the graphed line is x+2y=5. what is the x-intercept of the graph?
Stella [2.4K]
The x-intercept is where the graph crosses the x-axis. that happens when y=0.

x + 2(0) = 5
x = 5

x-intercept is 5
4 0
3 years ago
The diagonals of quadrilateral ABCD
kap26 [50]

Answer:

Step-by-step explanation:

16 ae =x

6 0
3 years ago
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