What are the slope and the y-intercept of the linear function that is represented by the equation?

deff fn [24]

$9x-14-2x=5(2x-6)\qquad\text{use distributive property}\\\\(9x-2x)-14=(5)(2x)+(5)(-6)\\\\7x-14=10x-30\qquad\text{add 14 to both sides}\\\\7x=10x-16\qquad\text{subtract 10x from both sides}\\\\-3x=-16\qquad\text{divide both sides by (-3)}\\\\\boxed{x=\dfrac{16}{3}}$

8 0

3 years ago

An automobile manufacturer is preparing a shipment of cars and trucks on a cargo ship that can carry 21,600 Tons. The cars weigh

inysia [295]

Answer:

Number of trucks (y) that can be shipped if the number of cars (x) is known $=\frac{21,600-3.6x}{7.5}$

Step-by-step explanation:

A cargo ship can carry 21,600 Tons.

Let x denotes number of cars and y denotes number of trucks.

The cars weigh 3.6 tons each and the trucks weigh 7.5 tons each.

Therefore,

$3.6x+7.5y=21,600$

Now write y in terms of x.

$7.5y=21,600-3.6x\\y=\frac{21,600-3.6x}{7.5}$

Number of trucks (y) that can be shipped if the number of cars (x) is known $=\frac{21,600-3.6x}{7.5}$

3 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

A car dealership has various combinations of vehicles in their car lot, all of which have an equally likely change of being sele

Effectus [21]

Answer:

The probability of a car being selected will be given by :the number of car required/ the total number of cars

Step-by-step explanation:

Probability is the likelihood of an event occurring.

This is given by : number of required outcome/number of possible outcome

7 0

3 years ago

A group of 6 students is surveying their classmates to get feedback about different clubs they're involved in. If each surveys m

galben [10]

Answer:

The domain would be given by D = {X ≥ 2} X = [2, Z]. Since the variable Z is the number of children in the school. And the 6 children should not survey the same person, it would be Z / 6 for each interviewer.

Step-by-step explanation:

- If the group of children surveys more than 2 classmates, it means that the number with which the survey begins is 12 students.

And since the maximum number of students in the school is given by the variable of Z, then Z is the number with which the domain closes.

The rank would be given by the set of [2, Z]

Z / 6 being the maximum number of children surveyed by 1 interviewer.

8 0

3 years ago