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STALIN [3.7K]
3 years ago
8

This dot plot is not symmetric, and the data set has two

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
5 0

Answer:

The best measure of center for this dot plot is the median.

Step-by-step explanation:

miskamm [114]3 years ago
5 0
The median is your answer
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If Belinda wants to earn AT LEAST $400 profit (money earned after her expenses), how many pies does she need to sell?
Monica [59]

Step-by-step explanation:

3 0
3 years ago
the sides of one right triangle are 6,8 and 10.the sides of another right triangle are 10,24 and 26.determine if the triangle ar
valkas [14]
So the ratio must be the same for the triangle to be the same
smallest side of 1 right triangle to smalles side of other right trigle shoudl be same as largest  side of 1 right trignale to largest side of other right triangle and also middle side


6:10 should equal 10:26 should equal 8:24
treat as fraction
6/10=10/26=8/24?
3/5=5/13=1/3
we know that 3/5 is not equal to 1/3 so they are NOT SIMILAR

ratios are
3:5
1:3
5:13


the perimiter of the smaller is 6+8+10=24
perimiter of larger is 10+24+26=60
ratio of perimiters larger to smaller is 60:24=5:2

area is 1/2 base times height
longest side=hypotonuse
therefor other 2 sides must be base and height

area of smaller=8 times 6 times 1/2=24

area lf larger=10 times 24 times 1/2=120
ratio of larger ot smaller is 120:24=5:1



not similar


ratio of perimiter larger to smaler=5:2

ratio oif area larger to smaller=5:1
5 0
4 years ago
So, I need to evaluate 1/2n + 1/6 when n = 1/3.​
Semenov [28]

Answer:

1/3

Step-by-step explanation:

First, plug in n to the equation

1/2(1/3)+1/6

Now multiply 1/2*1/3

1/6+1/6

Simplify

2/6-->1/3

Hope this helps!

3 0
3 years ago
Read 2 more answers
Nadine has 3 yard of ribbon to wrap birthday party favors if each favor use 1/5 yards of ribbon how many favors can nadine wrap
nata0808 [166]
I think the answer is 15 Hope this helps

4 0
4 years ago
The relationship 1/sin(θ) is equivalent to which of the following trigonometric functions?
Helga [31]
\bf sin(\theta)=\cfrac{1}{csc(\theta)}
\qquad 
% cosine
cos(\theta)=\cfrac{1}{sec(\theta)}
\qquad 
% tangent
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}
\\\\\\
% cotangent
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad 
% cosecant
\boxed{csc(\theta)=\cfrac{1}{sin(\theta)}}
\qquad 
% secant
sec(\theta)=\cfrac{1}{cos(\theta)}
6 0
4 years ago
Read 2 more answers
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