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cluponka [151]
3 years ago
7

Circle the correct answer sound cannot travel through

Chemistry
1 answer:
Bad White [126]3 years ago
8 0
A a solid is the correct answer
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Toothpaste is an alkali. How could you use the toothpaste to show that red cabbage is an indicator?
Alecsey [184]

Answer:

PUT THE TOOTHPAST ON CABBAGE AND CHECK IT OUT AFTER A DAY

3 0
3 years ago
What is the volume of 88.2 g of silver metal (density = 10.50 g/cm^3)
babymother [125]

Answer:

The answer is

<h2>8.4 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}

From the question

mass = 88.2 g

density = 10.5 g/cm³

The volume is

volume =  \frac{88.2}{10.5}

We have the final answer as

<h3>8.4 mL</h3>

Hope this helps you

8 0
3 years ago
Read 2 more answers
HURRY! 10 POINTS!!
frosja888 [35]

Answer:

Weak bonds require less energy to form than strong bonds

Explanation:

According to Coulomb's law, the force between two species is inversely proportional to the distance between them. That said, the bigger the atoms are, the greater the bond length should be to form a molecule.

As a result, for a greater bond length, the attraction force is lower than for a shorter bond length. This implies that large atoms would form weak bonds and small atoms would form strong bonds.

Bond energy is defined as the amount of energy required to break the bond. If a bond is weak, it would require a low amount of energy to break it. This is also true for energy of formation, as it's the same process taking place in the opposite direction.

6 0
4 years ago
What is the hydroxide-ion concentration in a solution formed by combining 200. ml of 0.16 m hcl with 300. ml of 0.091 m naoh at
iren2701 [21]
34 degrees long that way you pass the exam
8 0
4 years ago
Write the balanced nuclear equation for β− decay of silicon−32. Include both the mass numbers and the atomic numbers with each n
weqwewe [10]

Answer:

^{32}_{14}Si\rightarrow ^{32}_{15}P+e^-+\bar{v}_e

Explanation:

Beta decay conserves the lepton number. In \beta^- decay, the atomic number of the element increases which is accompanied by the release of  an electron antineutrino, e^-+\bar{v}_e.

For example:-

^A_ZX\rightarrow ^A_{Z+1}X+e^-+\bar{v}_e

The \beta^- decay of silicon-32 is shown below as:-

^{32}_{14}Si\rightarrow ^{32}_{15}P+e^-+\bar{v}_e

8 0
4 years ago
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