<span>A.to calculate the amount of product that would form
</span>
I need help on this one too I think it might be (b)
<u>Answer:</u> The amount of energy absorbed by water is 5390 Calories
<u>Explanation:</u>
To calculate the amount of heat absorbed at normal boiling point, we use the equation:

where,
q = amount of heat absorbed = ?
m = mass of water = 10 grams
= latent heat of vaporization = 539 Cal/g
Putting values in above equation, we get:

Hence, the amount of energy absorbed by water is 5390 Calories