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Naily [24]
3 years ago
14

-11 2/3 * (-4 1/5)=

Mathematics
2 answers:
WARRIOR [948]3 years ago
5 0

Answer:

  • 49

Step-by-step explanation:

<u>Simplify:</u>

  • -11 2/3 * (-4 1/5)=
  • 11 2/3 * 4 1/5 =
  • 35/3 * 21/5 =
  • 35/5*21/3 =
  • 7*7 =
  • 49
Solnce55 [7]3 years ago
3 0

\large\blue{\tt Given :-}

\to\tt - 11\frac{2}{3} (-4\frac{1}{5})

\large\orange{\tt To \:  Find :-}

\to\tt Simplify \:  the \:  sum

\large\green{\tt Solution :-}

\tt -11\frac{2}{3} (-4\frac{1}{5})

=\tt 11\frac{2}{3} \times 4\frac{1}{5}

=\tt\frac{35}{3} \times \frac{21}{5}

= \tt\frac{\cancel{35}}{\cancel5} \times \frac{\cancel{21}}{\cancel3}

= \tt 7 \times 7

= \underline{\boxed{\blue{\tt 49}}}

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In how many ways can we choose a 12 member jury from 30 possible people?
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This is a problem dealing with permutations and combinations.
Order does not matter in this problem.
Since order doesn't matter, it is a combination.
Repetition matters, since you can't have the same person count as two people.

There are twelve slots.

_ _ _ _ _ _ _ _ _ _ _ _ 

Each slot needs to be multiplied by the next.

_*_*_*_*_*_*_*_*_*_*_*_

Now we have to fill in the slots.
Each slot will be filled with a number one less than the one before it. It has to be one less, since repetition matters.
The numbers will be decreasing from 30, since there are 30 possible people.

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Multiply these numbers together and you get your answer.

41,430,393,164,160,000 ways
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Eric bought a ruler for $1.29 and an eraser for $0.39. He paid with $2.00. What is the correct amount of change he should get ba
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Step-by-step explanation:

8 0
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How many degrees is 7/4 of a semicircle?
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5 0
2 years ago
Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....
lina2011 [118]

Answer:Answer:

\sum\left {{7} \atop {1}} \right -n(3+n)

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as S_n = \frac{n}{2}[2a+(n-1)d]

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 =  \frac{7}{2}[-8+(6)(-2)]\\\\S_7 =  \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70

The sum of the nth term of the sequence will be;

S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n =  \frac{-6n}{2} -  \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)

The sigma notation will be expressed as \sum\left {{7} \atop {1}} \right -n(3+n). <em>The limit ranges from 1 to 7 since we are to  find  the sum of the first seven terms of the series.</em>

3 0
3 years ago
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