So I'm hoping you mean 6, or else the probability is 0. So the possible ways of getting a sum of 6 is 1&5, 2&4, 3&3, 4&2, 5&1. There are 36 different ways of rolling the dice, so divide the 5 possible ways by 36. Then, we need to add the possibility of getting at least one 6 in the roll. It doesn't matter what the other die is, so for each die, the probability is 1/6, and for both, the probability is 2/6. Add this to the probability of getting a sum of 6, and you get your answer.
Answer:
a) 4(t - r) = 4(6 - 2.5) = 4 x 3.5 = 14
b) 4t - r = (4 x 6) - 2.5 = 24 - 2.5 = 21.5
c) 2(3t - 10) = 2(3 x 6 - 10) = 2(18 - 10) = 2 x 8 = 16
d) (t - 2)² = (6 - 2)² = 4² = 4 x 4 = 16
e) cannot decipher the equation
f) 6r + t = 6 x 2.5 + 6 = 15 + 6 = 21
(20 + 12) - 8, since the question states n is EIGHT less than the sum of 20 and 12.
Answer:
its 3.
Step-by-step explanation:
