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Alex17521 [72]
4 years ago
8

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics
2 answers:
pochemuha4 years ago
5 0

Answer:

log base 6 of the cube root of 6 matches with 1/3

-3 log 5 of 25 matches with -6

log base 2 of the 4th root of 8 matches with 3/4

log base 3 of 1/81 matches with -4

Sergio [31]4 years ago
3 0

Answer:

Step-by-step explanation:

Let's simplify all the possible answers:

  • log_{6} \sqrt[3]{6} = log_{6} (6\frac{1}{3} ) = \frac{1}{3}
  • log_{3} \frac{1}{81} = log_{3} (3^{-4} ) = -4
  • -3log_{5} 25 \\ = -3log_{5} (5^{2} ) = -3*2 = -6
  • log_{2} \sqrt[4]{8} = log_{2} \(2^{\frac{3}{4} } = \frac{3}{4}

Hope it will find you well.

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Are these right they are for my best friend and I have no clue HELP ME
Lady bird [3.3K]
9. Square
10. Square
11. Rectangle
12. Rectangle
13. Square
14. Triangle

Explanation:
I think you may have confused parallel and perpendicular for some of the questions. Also, a cube has square sides and base, so any crossection parallel or perpendicular will also be square. I hope this is helpful!
7 0
2 years ago
(1 point) The effectiveness of a new bug repellent is tested on 18 subjects for a 10 hour period. Based on the number and locati
jolli1 [7]

Answer:    

z=1.59

If we compare the p value and the significance level given \alpha=0.025 we see that p_v>\alpha so we can conclude that we fail to reject the null hypothesis, so we can conclude that the mean repellency of the new bug repellent is greater than 89% at 0.025 of signficance.    

Step-by-step explanation:    

1) Data given and notation    

\bar X=0.92 represent the mean effectiveness of a new bug repellent for the sample    

\sigma=0.08 represent the population standard deviation for the sample    

n=18 sample size    

\mu_o =0.89 represent the value that we want to test  

\alpha=0.025 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to determine if the mean repellency of the new bug repellent is greater than 89% or 0.89, the system of hypothesis would be:    

Null hypothesis:\mu \leq 0.89    

Alternative hypothesis:\mu > 0.89    

We don't know the population deviation, and the sample size <30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{0.92-0.89}{\frac{0.08}{\sqrt{18}}}=1.59    

Calculate the P-value    

First we need to calculate the degrees of freedom given by:

df=n-1=18-1=17

Since is a one-side upper test the p value would be:    

p_v =P(t_{17}>1.59)=0.065

In Excel we can use the following formula to find the p value "=1-T.DIST(1.59;17;TRUE)"  

Conclusion    

If we compare the p value and the significance level given \alpha=0.025 we see that p_v>\alpha so we can conclude that we fail to reject the null hypothesis, so we can conclude that the mean repellency of the new bug repellent is greater than 89% at 0.025 of signficance.    

6 0
4 years ago
For security, a credit card number is coded in the following way, so that it can be sent as a message. Subtract each digit from
Semenov [28]
6898 7657 6541 9068 is the coded credit card #
7 0
3 years ago
Solve for x. Enter you answer in the box.
Nikitich [7]

Answer:

x = 6

Step-by-step explanation:

AD is a midline segment and divides EB and EC  in the same proportion, that is

\frac{EA}{AB} = \frac{ED}{DC}

Substituting in values gives

\frac{16}{x+2} = \frac{12}{24} = \frac{1}{2} ( cross- multiply )

5x + 2 = 32 ( subtract 2 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

8 0
4 years ago
54+54788347589535222
enyata [817]
5.4788348e+16. ........
6 0
3 years ago
Read 2 more answers
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