This is basically a simple problem to understand. The only thing that needs to be done is to divide the mass of the sun by the mass of mercury. It will give the required result.
Number of times the mass of sun is greater than
the mass of mercury = 21.3525×102921.3525×1029/<span>328.5×1021328.5×1021
= </span><span>7.1783629e+15
I hope that this is the answer that you were looking for and it has come to your great help.</span>
Do 10 to the sixth power first then multiply that by 7 you use PEMDAS
Answer:
<ABC = 49°
Step-by-step explanation:
The sum of two supplementary angle is 180. From the diagram, the two angles are 3x+4 and 8x+11. IF this two angles are supplementary then;
3x+4+8x+11 = 180
11x+15= 180
11x = 180-15
11x = 165
x = 165/11
x = 15
From the attached diagram, <ABC = 3x+4
<ABC = 3(15)+4
<ABC = 45+4
<ABC = 49°
The expected completion time is μ = 40 weeks.
The random variable, X = 38 weeks (the probable time)
If the standard deviation is σ, then the z-score is z = (x - μ)/σ.
Let us test the given standard deviations.
When σ=1,
z = (38-40)/1 = -2
From standard tables,
P(x<=38) = P(z<=-2) = 0.0228 =2.3%
When σ=2,
z = (38*40)/2 = -1
P(x<=38) = P(z<=-1) = 0.1587 = 15.9%
When σ=4,
z = (38-40)/4 = -0.5
P(x<=38) = P(z<=-0.5) = 0.3085 = 30.9%
Answers:
z=1 => 2.3%
z=2 => 16% (approx)
z=4 => 31% (approx)
Answer:
I think its 20 to 60 or something like that....
Step-by-step explanation:
