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STatiana [176]
3 years ago
5

Find the twenty-fifth term of an arithmetic sequence if the first term is-1 and the common difference is 5. Write the first thre

e terms of an arithmetic sequence in which the twenty-first term is 17 and the fiftieth term is 75. 10. 11
Mathematics
1 answer:
denis-greek [22]3 years ago
8 0

Answer:

1). T_{25}=119

2). T_{1}=-23

T_{2}=-23+2=-21

T_{3}=-23+4=-19

Step-by-step explanation:

First term of an arithmetic sequence is (-1) and common difference is 5.

Then we have to find twenty fifth term of this arithmetic sequence.

Since explicit formula of an arithmetic sequence is represented by

T_{n}=a+(n-1)d

Where T_{n} represents nth term of the sequence.

a = first term

n = number of term

and d = common difference

Now we will find 25th term of this sequence.

T_{25}=(-1)+(25-1)5

= (-1) + 120

= 119

Similarly in second part of this question we have to find first three terms of an arithmetic sequence in which

T_{21}=17 and

T_{50}=75

Now from the explicit formula

17 = a + (21 - 1)d

17 = a + 20d   --------(1)

75 = a + (50 - 1)d

75 = a + 49d --------(2)

Now we subtract equation 1 from 2

75 - 17 = 49d - 20d

29d = 58

d = \frac{58}{29}=2

By putting d = 2 in equation 1

17 = a + 20×2

17 = a + 40

a = 17 - 40

a = -23

Therefore, first three terms of this sequence will be

T_{1}=-23

T_{2}=-23+2=-21

T_{3}=-23+4=-19

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Given

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