Convert 1 3/5 to an improper fraction;
-1 × 5 + 3/5 ÷ -2/3
Simplify 1 × 5 to 5
-5 + 3/5 ÷ -2/3
Simplify 5 + 3 to 8
-8/5 ÷ -2/3
Use this rule: a ÷ b/c = a × c/b
-8/5 × 3/-2
Use this rule; a/b × c/d = ac/bd
-8 × 3/5 × - 2
Simplify 8 × 3 to 24
-24/5 × -2
Simplify 5 × -2 to -10
- 24/-10
Move the negative sing to the left
-(-24/10)
Simplify 24/10 to 12/5
-(-12/5)
Simplify brackets
12/5
Convert to a mixed fraction
<u>= 2 2/5</u>
2
3
−
1
1
=
3
+
3
2
3
x
−
11
=
x
3
+
3
32x−11=3x+3
2
3
−
1
1
=
3
+
3
2
x
3
−
11
=
x
3
+
3
32x−11=3x+3
2
Find common denominator
2
3
−
1
1
=
3
+
3
2
x
3
−
11
=
x
3
+
3
32x−11=3x+3
2
3
+
3
(
−
1
1
)
3
=
3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x+33(−11)=3x+3
3
Combine fractions with common denominator
2
3
+
3
(
−
1
1
)
3
=
3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x+33(−11)=3x+3
2
+
3
(
−
1
1
)
3
=
3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)=3x+3
4
Multiply the numbers
2
+
3
(
−
1
1
)
3
=
3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)=3x+3
2
−
3
3
3
=
3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33=3x+3
5
Find common denominator
2
−
3
3
3
=
3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33=3x+3
2
−
3
3
3
=
3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33=3x+33⋅3
6
Combine fractions with common denominator
2
−
3
3
3
=
3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33=3x+33⋅3
2
−
3
3
3
=
+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33=3x+3⋅3
7
Multiply the numbers
2
−
3
3
3
=
+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33=3x+3⋅3
2
−
3
3
3
=
+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33=3x+9
8
Multiply all terms by the same value to eliminate fraction denominators
2
−
3
3
3
=
+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33=3x+9
3
⋅
2
−
3
3
3
=
3
(
+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33=3(3x+9)
9
Cancel multiplied terms that are in the denominator
3
⋅
2
−
3
3
3
=
3
(
+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33=3(3x+9)
2
−
3
3
=
+
9
2
x
−
33
=
x
+
9
2x−33=x+9
10
Add
3
3
33
33
to both sides of the equation
2
−
3
3
=
+
9
2
x
−
33
=
x
+
9
2x−33=x+9
2
−
3
3
+
3
3
=
+
9
+
3
3
2
x
−
33
+
33
=
x
+
9
+
33
2x−33+33=x+9+33
11
Simplify
Add the numbers
Add the numbers
2
=
+
4
2
2
x
=
x
+
42
2x=x+42
12
Subtract
x
x
from both sides of the equation
2
=
+
4
2
2
x
=
x
+
42
2x=x+42
2
−
=
+
4
2
−
2
x
−
x
=
x
+
42
−
x
2x−x=x+42−x
13
Simplify
Combine like terms
Multiply by 1
Combine like terms
=
4
2
x
Answer:
I think it's 420 pls correct me if I'm wrong
Using a linear function, it is found that the costs are given as follows:
- With r rides: C(r) = 20 + 4r.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
Considering the price of admission and the price per ride, the y-intercept is of 20 and the slope is of 4, the cost for r rides is given by:
C(r) = 20 + 4r.
Hence, for 6 rides, the cost is given by:
C(6) = 20 + 4 x 6 = $44.
More can be learned about linear functions at brainly.com/question/24808124
#SPJ1
Since the 5 is in the <em>tens </em>place, that means it represents <em>5 tens</em>, or 50.
