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3 years ago

What is the solution for the equation (x-5)^2+3(x-5)+9=0 Use u substitution and the quadratic formula to solve?

Mathematics

1 answer:

Mariulka [41]3 years ago

4 0

Answer:

Here is the answer.

x= 1/2(7+3i√3) and 1/2(7-3i√3)

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Last question please help

Grace [21]

Juan won and has a score of 8.5, the difference between there score is 3.5.

4 0

3 years ago

MN and KL are parallel. If JM = 6, MK = 12, and LN = 18, what is NJ?

Galina-37 [17]

6/12=X/18
Using the ratio of 18:12, you multiply 18/12 with 6, which equals 9.

Answer: NJ=9

5 0

3 years ago

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Ron is tiling a countertop he needs to place 54 square titles in each of 8 rows to cover the counter

DiKsa [7]

He would only be able to make 6 rows with 3/4 of another

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2 years ago

A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be

Natali [406]

Options

The circle at the new location has _____________ the original circle.

- the same center as

- twice the circumference of

- half the radius of

- the same area as

Answer:

the same area as

Step-by-step explanation:

When a circle is translated and reflected, the center of the circle will change; however, its area, circumference, radius and diameter remain the same.

This is so because, translation and reflection only affect the positioning of the circle not the size.

Considering the above analysis, we can conclude that option d answers the question correctly.

8 0

3 years ago

One of the tables shows a proportional relationship. Graph the line representing the proportional relationship from this table i

Mkey [24]

Answer:

Table C

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

Find the value of the constant of proportionality in each table

Table A

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-3$ ------> $k=-3/-1=3$

This table has different values of k

therefore

the table A does not represent a proportional relationship

Table B

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=3$ ------> $k=3/1=3$

This table has different values of k

therefore

the table B does not represent a proportional relationship

Table C

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=2$ ------> $k=2/1=2$

For $x=2, y=4$ ------> $k=4/2=2$

This table has the same value of k

therefore

the table C represent a proportional relationship

Table D

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=2$ ------> $k=2/1=2$

For $x=2, y=6$ ------> $k=6/2=3$

This table has different values of k

therefore

the table D does not represent a proportional relationship

3 0

3 years ago

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