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masya89 [10]
3 years ago
14

The Caesar Cipher has 25 different shifts to try.

Computers and Technology
1 answer:
statuscvo [17]3 years ago
3 0

Answer:

D. 25x24x23x22x21.....3x2x1.

Explanation:

The ceasar cipher is a encryption technique, that uses a combination of information or keys to encrypt an information.

The 25 shift ceasar cipher has 25 different combinations, so the number of probable random cipher substitution is 25!,

That is = 25 × 24×23× 22×..... ×2×1.

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Write a function that will sum all of the numbers in a list, ignoring the non-numbers. The function should takes one parameter:
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In python 3.8:

def func(value_list):

   lst = [x for x in value_list if type(x) == int or type(x) == float]

   return sum(lst)

print(func(["h", "w", 32, 342.23, 'j']))

This is one solution using list comprehensions. I prefer this route because the code is concise.

def func(value_list):

   total = 0

   for x in value_list:

       if type(x) == int or type(x) == float:

           total += x

   return total

print(func(["h", "w", 32, 342.23, 'j']))

This is the way as described in your problem.

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3 years ago
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Answer:

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Explanation:

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2 years ago
I need an answer and fast What happens if a sequence is out of order?
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Answer:

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Explanation:

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3 years ago
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A program is required to three (3) numbers. calculate and print their total
podryga [215]

A program that is required to three (3) numbers. calculate and print their total is given below:

<h3>The Program</h3>

import java.util.Scanner;

public class SumAndAverage {

public static void main(String[ ] args) {

System.out.println("Enter three numbers - ");

// Accepting and finding sum of numbers.

int sum = 0;

Scanner sc = new Scanner(System.in);

for (int i = 0; i < 3; i++)

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System.out.println("Sum - " + sum);

System.out.println("Average - " + (sum / 3f));

}

}

The output would request three different numbers, then add them up, and display the output of the sum and then display or print their total


Read more about programming here:

brainly.com/question/23275071

#SPJ1

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Priority levels hehe good luck!
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