Answer:
a. 0.01
b. 0.001
c. The identification field of the packet fragment can be used to uniquely identify and collate the fragments lost in transmission.
Explanation:
The probability of losing a packet is 10% or 0.1, so the probability of losing the packet twice during transmission;
= 0.1 x 0.1 = 0.01
When any fragments have been part of the transmission, the probability of the packet is dependent on the fragments;
= 0.01 x 0.1 = 0.001
The identification field is a unique 16-bit value assigned to an IPv4 packet, when a packet is fragmented for transmission, its field is used to collate the unique fragments in the packet.
Session Initiation Protocol, brainliest ?
ARPANET would not carry it
B) Contact metamorphism can occur.
Answer:
bears = {"Grizzly":"angry", "Brown":"friendly", "Polar":"friendly"}
for bear in bears:
if bears[bear] == "friendly":
print("Hello, "+bear+" bear!")
else:
print("odd")
Explanation:
A dictionary called bears is given. A dictionary consists of key-value pairs.
You need to check each key-value pairs in bears and find the ones that have "friendly" as value using a for loop and if-else structure. In order to access the values of the dictionary, use the dictionary name and the key (inside the loop, the key is represented as bear variable). If a key has a value of "friendly", print the greeting. Otherwise, print "odd".
