The device that this network administrator is most likely installing in the infrastructure is a Network Attached Storage (NAS).
<h3>What is a
Network Attached Storage (
NAS)?</h3>
A Network Attached Storage (NAS) can be defined as a file-dedicated storage device that is designed and developed to enable multiple end users and other heterogeneous client devices to store, share and retrieve data anywhere from a centralized disk, especially through a network.
In this context, we can infer and logically conclude that a Network Attached Storage (NAS) is the device that this network administrator is most likely installing in the infrastructure because it doesn't require licensing and the data stored on it at the file level can be accessed anywhere.
Read more on Network Attached Storage here: brainly.com/question/14456295
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Answer:
The "Page breaks before" option is the correct approach.
Explanation:
- This attribute specifies whether such a page interruption could perhaps appear just before any component to something which applies.
- This says that you would like this particular section to succeed at the beginning of that same page, irrespective of what it's about, they are being used for paged multimedia, for example, printed publications and otherwise texts or paperwork.
Answer:
You should be strong, and be sure about what you want to say. Make sure when you speak it is clear, and makes sense.
Explanation:
If you don't speak up or sound like you know what you are talking about. I like to think of it as dancing. Act like you own the stage, or in your case, like you own the presentation. Also, I suggest you speak to your teacher in private, about him ignoring you. If I were you, I would look for newer friends. Ones that won't ignore you.
<span>i believe the answer is C</span>
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int minn=INT_MAX;
int maxx=INT_MIN;
int n1,n2,n3,n4,n5;
cout<<"enter five Numbers:";
//read 5 Numbers
cin>>n1>>n2>>n3>>n4>>n5;
// find maximum
if(n1>maxx)
maxx=n1;
if(n2>maxx)
maxx=n2;
if(n3>maxx)
maxx=n3;
if(n4>maxx)
maxx=n4;
if(n5>maxx)
maxx=n5;
// find minimum
if(n1<minn)
minn=n1;
if(n2<minn)
minn=n2;
if(n3<minn)
minn=n3;
if(n4<minn)
minn=n4;
if(n5<minn)
minn=n5;
// print maximum and minimum
cout<<"maximum of five numbers is: "<<maxx<<endl;
cout<<"minimum of five numbers is: "<<minn<<endl;
return 0;
}
Explanation:
Declare two variables "minn" & "maxx" and initialize them with INT_MAX and INT_MIN respectively.Then read the five number from user and compare it with "minn" & "maxx" ,if input is greater than "maxx" then update "maxx" or if input is less than "minn" then update the "minn". After all the inputs, "minn" will have smallest and "maxx" will have largest value.
enter five Numbers:5 78 43 55 12
maximum of five numbers is: 78
minimum of five numbers is: 5
