Which model could represent the solution to 2/3

A light bulb filament is one-hundredth of an inch thick, with an allowable error of 2 percent. What is the least allowable thick

Andreyy89

Answer:

0.00998 Inches

Step-by-step explanation:

Thickness of the light bulb filament = 0.01 Inch

Allowable error = 2%.

2% of 0.01 = 0.02 X 0.01 =0.0002 Inch

Therefore, the allowable thickness of the bulb filament

$=0.01 \pm 0.0002 $ Inches$

We can then calculate the least allowable thickness of the filament as:

$=0.01 - 0.0002 \\=0.00998$ Inches$

The least allowable thickness of the filament is 0.00998 Inches.

3 0

3 years ago

This is hard can someone help ?

Anastaziya [24]

6. Often, judging the symmetry and skewness of such distributions is not easy to do by eye, especially when they are asymmetrical or skewed in different ways. Here, the mean of set A is about 7, so the data is skewed to the left more than for set B, which has a mean of about 5.4--closer to the middle of the range.

Both data sets have the same range: 2–10. Set A's mode of 8 is higher than set B's mode of 6.

Hence, the only true statement appears to be

... B. Set B has the lesser mean.

7. For each of the 3 choices of meat, there are 3 choices of bread, and for each of any of those 9 choices, there are 4 choices of condiment—a total of 3×3×4 = 36 choices in all. The best answer is ...

... C. 36

8. The pie chart tells you 5% of the $4800 of monthly income is spent on transportation. That amount is .05×$4800 = ...

... C. $240

6 0

3 years ago

Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29

Alborosie

Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ $\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}$

⇒ $\frac{15}{Sin 29} = \frac{20}{sin B}$

Using value of sin 29°

⇒ $\frac{15}{0.49} = \frac{20}{sin B}$

Cross multiplying both side.

⇒ Sin B= $\frac{20\times 0.49}{15} = 0.65$

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒ $29+41+B= 180$

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

$\frac{b}{SinB} = \frac{c}{SinC}$

⇒ $\frac{20}{sin41} = \frac{C}{sin110}$

Using the value of sine and cross multiplying both side.

⇒ C= $\frac{20\times 0.94}{0.65} = 28.92$

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= $(15+20+28.92)= 63.9$

∴ Perimeter of triangle= 63.9 units

7 0

3 years ago

The Cobb family of Fremont is looking at ways to decrease their home water and energy usage. Their current electric hot-water he

OverLord2011 [107]

Answer:

ai) 73000 gal/yr

aii) $730 per year

b) 1000 days

Step-by-step explanation:

ai) The water usage per day is ...

(4 showers/day)(10 min/shower)(5 gal/min) = 200 gal/day

Then the usage per year is ...

(200 gal/day)(365 days/yr) = 73,000 gal/yr

__

aii) The cost of electricity is the cost of heating half the water usage, so is ...

(0.20 kWh/gal)(1/2)(73,000 gal/yr)($0.10/kWh) = $730/yr

__

b) The current daily cost of electricity for heating water is ...

($730/yr)/(365 days/yr) = $2/day

If the cost is cut in half, it will be $1 per day. That means the savings is $1 per day, so it will take 1000 days to recover the $1000 initial cost. (Effectively, the average cost for the first 1000 days is the same as if the water heater had not been replaced.)

5 0

4 years ago

Find the area of the shaded region.

kolbaska11 [484]

Answer:

$\boxed{ \tt\longrightarrow \: Area \: Of \: Shaded \: region \: =\boxed{ \tt 39 \: in²}}$