All categories

3 years ago

Which of the following is a valid use of the associative property of addition?

2 answers:

8 0

$\text{Associative property:}\\\\a+(b+c)=(a+b)+c\\\\\text{Find the equation that matches with the associative property formula}\\\\\text{When you add them, you should get the same answer no matter what}\\\text{position the numbers are in}\\\\(23+15)-5\\\\38-5=33\\\\23+15-5\\\\38-5=33\\\\\text{This means that A would be your answer}\\\\\boxed{A. (23 + 15) - 5 = 23+ (15 - 5)}$

Natasha_Volkova [10]3 years ago

3 0

Answer:

Step-by-step explanation:

(25+15)-5=40-5=35

25+(15-5)=25+10=35

You might be interested in

Help!! I have been struggling on this!

LiRa [457]

Answer:

as [tex]\cos(\theta)=\srqt{1-\sin^2(\theta)}\[tex]

and since theta is in second quadrant, where cosine is negative,

so -√(1-z²)

6 0

3 years ago

PLLSSSS HELP QUICKLY .

omeli [17]

A :) is the correct anwser

6 0

3 years ago

Read 2 more answers

hichkok12 [17]

Answer:

The coordinates of C(22/3, 7)

Step-by-step explanation:

Partitioning between two points A and B in the ratio a:b.

The x-coordinate of the point of partition C is found at

XC = XA*(b/(a+b)+XB(a/(a+b) ..............(1)

Similarly, the x-coordinate of the point of partition is found at

YC = YA*(b/(a+b)+YB(a/(a+b)...............(2)

Given A(8,8), B(4,2), partition ratio of A:B = 1:5,

substitute in (1)

XC = 8*5/6+4*1/6 = 44/6 = 22/3

YC = 8*5/6 + 2*1/6 = 42/6 = 7

The coordinates of C(22/3, 7)

7 0

3 years ago

A man is five times as old as his son. Four years ago the man was thirteen times as old as his son.

skad [1K]

Answer:

Age of son = 6 years

Age of man = 5×6 = 30 years

Step-by-step explanation:

GIVEN :-

A man is 5 times as old as his son. (In Present)
4 years ago , the man was 13 times as old as his son

TO FIND :-

The present ages of the man & his son.

SOLUTION :-

Let the present age of son be 'x'.

⇒ Present age of man = 5x

4 years ago ,

Age of son = (Present age of son) - 4 = x - 4

Age of man = (Present age of man) - 4 = 5x - 4

The man was thirteen times as old as his son. So,

$=> 5x - 4 = 13(x - 4)$

Now , solve the equation.

Open the brackets in R.H.S.

$=> 5x - 4 = 13x - 52$

Take 5x to R.H.S. and -52 to L.H.S. Also , take care of their signs because they are getting displaced from L.H.S. to R.H.S. or vice-versa.

$=> 13x - 5x = 52 - 4$

$=> 8x = 48$

Divide both the sides by 8

$=> \frac{8x}{8} = \frac{48}{8}$

$=> x = 6$

CONCLUSION :-

Age of son = 6 years

Age of man = 5×6 = 30 years

8 0

3 years ago

A square has an area of 16x^2 square inches. If the sides of the square were to increase by 2 units, what is the new area of the

kykrilka [37]

Answer:

16x² + 64x + 64

Step-by-step explanation:

Given

A = 16x²

Increasing the sides by 2, substitute x = x + 2 into A

A = 16(x + 2)² ← expand factor using FOIL

= 16(x² + 4x + 4 ) ← distribute

= 16x² + 64x + 64

4 0

3 years ago