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2 years ago

Hey, if you can help I would love it. Subtract 3 from the product of 8 and 5

Mathematics

2 answers:

Dominik [7]2 years ago

7 0

Answer:

Hey mate......

Step-by-step explanation:

This is ur answer....

Hope it helps!

Brainliest pls....

Follow me! ;)

balandron [24]2 years ago

4 0

Answer:

Step-by-step explanation:

Subtracting 3 from the product of 8 and 5 means that the 8 and 5 need to be multiplied first.

Brackets, in the order of operations, come before other operators, other than square root, square, and the like. In general, multiplication and division would be done before subtraction, so the bracket goes over 5 x 8 and not 8 - 3.

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A builder is building a fence with 6-inch-wide wooden boards, arranged side-by-side with no gaps. How many boards are needed to

Varvara68 [4.7K]

Answer:

25 wooden boards

Step-by-step explanation:

Given that:

Width of wooden board = 6 inches

Number of boards required to build a fence of 150 inches long if there are no gaps :

The lenght of fence / width of wooden board

= 150 inches / 6 inches

= 25 wooden boards

6 0

2 years ago

What is the answer?

emmainna [20.7K]

Answer:

C. 2.75P

Step-by-step explanation:

The original value was P.

It increased by 275%. That means it increased by 275% of P.

275% of P = 2.75P

The increase in value is 2.75P.

Now we add the increase to the original value of P to find today's value.

2.75P + P = 3.75P

Answer: C. 2.75P

5 0

3 years ago

Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters. What is the diagonal d

jolli1 [7]

Answer:

70.7 meters.

Step-by-step explanation:

We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.

Since we know that diagonal of a square is product of side length of square and $\sqrt{2}$ . So we will find diagonal of our given square plaza by multiplying 50 by $\sqrt{2}$ .

$\text{Diagonal distance across the plaza}=50\times \sqrt{2}$

$\text{Diagonal distance across the plaza}=50\times 1.414213562373095$

$\text{Diagonal distance across the plaza}=70.71067811865475\approx 70.7$

Therefore, diagonal distance across the plaza is 70.7 meters.

8 0

2 years ago

Solve the equation for x.<br><br> 1<br> 4<br> (2x + 8) = −16

dimaraw [331]

Answer:Let's solve your equation step-by-step.

(2x+8)=−16

Step 1: Simplify both sides of the equation.

(2x+8)=−16

(

)(2x)+(

)(8)=−16(Distribute)

x+2=−16

Step 2: Subtract 2 from both sides.

x+2−2=−16−2

x=−18

Step 3: Multiply both sides by 2.

2*(

x)=(2)*(−18)

x=−36

4 0

3 years ago

Read 2 more answers

Find the domain of the Bessel function of order 0 defined by [infinity]J0(x) = Σ (−1)^nx^2n/ 2^2n(n!)^2 n = 0

Snowcat [4.5K]

Answer:

Following are the given series for all x:

Step-by-step explanation:

Given equation:

$\bold{J_0(x)=\sum_{n=0}^{\infty}\frac{((-1)^{n}(x^{2n}))}{(2^{2n})(n!)^2}}\\$

Let the value a so, the value of $a_n$ and the value of $a_(n+1)$ is:

$\to a_n=\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}$

$\to a_{(n+1)}=\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}$

To calculates its series we divide the above value:

$\left | \frac{a_(n+1)}{a_n}\right |= \frac{\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}}{\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}}\\\\$

$= \left | \frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2} \cdot \frac {2^{2n}(n!)^2}{(-1)^2n x^{2n}} \right |$

$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)!^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |$

$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\= \left | \frac{x^{2n}\cdot x^2}{2^{2n} \cdot 2^2(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\$

$= \frac{x^2}{2^2(n+1)^2}\longrightarrow 0$ for all x

The final value of the converges series for all x.

8 0

3 years ago