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kenny6666 [7]
3 years ago
15

Hey, if you can help I would love it. Subtract 3 from the product of 8 and 5

Mathematics
2 answers:
Dominik [7]3 years ago
7 0

Answer:

Hey mate......

Step-by-step explanation:

This is ur answer....

<h2>B. (5×8) - 3</h2>

Hope it helps!

Brainliest pls....

Follow me! ;)

balandron [24]3 years ago
4 0

Answer:

B

Step-by-step explanation:

Subtracting 3 from the product of 8 and 5 means that the 8 and 5 need to be multiplied first.

Brackets, in the order of operations, come before other operators, other than square root, square, and the like. In general, multiplication and division would be done before subtraction, so the bracket goes over 5 x 8 and not 8 - 3.

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The length of a rectangle is twice as long as its width. The width is 104 inches,
valentina_108 [34]

Answer:

624

Step-by-step explanation:

the width is 104

if the length is doubled, that means the length is 208.

rectangles have 2 sets of equal sides

104 + 104 =208

208 + 208 = 416

416+208 = 624

8 0
3 years ago
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Jaime makes the following claim.
Sphinxa [80]

Jaime is incorrect, the angle does not depend on the radius of the circles.

<h3>Is Jaime correct?</h3>

Remember that an angle that defines an arc on a circle, does not depend on the radius of the circle.

So, if we have an angle with a measure of π/3 radians in a circle with a radius of 3 inches and an angle with a measure of π/3 radians in a circle with a radius of 6 inches, these two angles are exactly the same thing.

The radius of the circle only has an impact on the length of the arc defined by the angle.

So Jaime is clearly incorrect.

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brainly.com/question/17972372

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2 years ago
NEED HELP ASAP<br> Given G (-6,5) and H (2, -7), what is the length of GH
lesya692 [45]

\bold{\huge{\green{\underline{ Solution }}}}

\bold{\underline{ Given}}

  • <u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

\bold{\underline{To  \: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

\bold{\underline{Let's \:  Begin :- }}

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}

  • <u>Here</u><u>, </u><u> </u><u>x1</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>,</u><u> </u><u>x2</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>and </u><u>y1</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>y2</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u>

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>

\sf{ Distance \:GH = √( -6 - 2)² + ( 5 -(-7))²}

\sf{Distance\:GH= √(-8)^2+(5 + 7)^2}

\sf{Distance\:GH=√(-8)^2+(12)^2}

\sf{ Distance \:GH =√64 + 144 }

\sf{ Distance \:GH =√ 208}

\sf{ Distance\: GH = √ 2 × 2 × 2 × 2 × 13}

\sf{ Distance \:GH = 4√13}

\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}

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