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3 years ago

What is the factoring quadratic expression for 8x^2-18=0

Mathematics

2 answers:

Rus_ich [418]3 years ago

5 0

$8x^2-18=0\\
2(4x^2-9)=0\\
2(2x-3)(2x+3)=0\\
x=\frac{3}{2} \vee x=-\frac{3}{2}$

mash [69]3 years ago

3 0

$8x^2-18=0\ /:2\\\\4x^2-9=0\ \ \ \Leftrightarrow\ \ \ (2x)^2-3^2=0\ \ \ \Leftrightarrow\ \ \ (2x-3)(2x+3)=0\\\\2x-3=0\ \ \ \ \ \ \ or\ \ \ \ 2x+3=0\\\\2x=3\ /:2\ \ \ \ \ \ or\ \ \ \ 2x=-3\ /:2\\\\x=1.5\ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ x=-1.5$

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