Answer:
1 ≥ t ≤ 3
Step-by-step explanation:
Given
h(t) = -16t² + 64t + 4
Required
Determine the interval which the bar is at a height greater than or equal to 52ft
This implies that
h(t) ≥ 52
Substitute -16t² + 64t + 4 for h(t)
-16t² + 64t + 4 ≥ 52
Collect like terms
-16t² + 64t + 4 - 52 ≥ 0
-16t² + 64t - 48 ≥ 0
Divide through by 16
-t² + 4t - 3 ≥ 0
Multiply through by -1
t² - 4t + 3 ≤ 0
t² - 3t - t + 3 ≤ 0
t(t - 3) -1(t - 3) ≤ 0
(t - 1)(t - 3) ≤ 0
t - 1 ≤ 0 or t - 3 ≤ 0
t ≤ 1 or t ≤ 3
Rewrite as:
1 ≥ t or t ≤ 3
Combine inequality
1 ≥ t ≤ 3
I think 17.2 sorry if im wrong
The other factor would be (x + 4). We can find this by using synthetic division. To do this, we must first find the divisor, which would be 9, if we let x - 9 equal to zero and solve for x. Then, for the dividend, we can use the coefficients and constant term values.
<u>9</u>| 1 -5 -36
<u> 9 36</u>
1 4 0
Therefore, the other expression (x + 9) would be (x + 4). Hope this helped!
Answer:
A 1:6
Step-by-step explanation:
3:18 simply to 1:6
Answer:
-2
Step-by-step explanation:
