Answer:
The length between the two points is RT = 1.3 units
Step-by-step explanation:
The coordinates of the point R and T are R(2,1.2) and T(2,2.5).
Now, by DISTANCE FORMULA:
The distance between two coordinates P and Q with coordinate P(a,b) and Q(c,d) is given as:
![PQ = \sqrt{(a-c)^2 + (b-d)^2}](https://tex.z-dn.net/?f=PQ%20%20%3D%20%5Csqrt%7B%28a-c%29%5E2%20%20%20%2B%20%28b-d%29%5E2%7D)
So, here the distance RT = ![\sqrt{(2-2)^2 + (2.5 - 1.2)^2} = \sqrt{0^2 + (1.3)^2} = 1.3](https://tex.z-dn.net/?f=%5Csqrt%7B%282-2%29%5E2%20%20%2B%20%282.5%20-%201.2%29%5E2%7D%20%20%20%3D%20%5Csqrt%7B0%5E2%20%20%2B%20%281.3%29%5E2%7D%20%20%20%3D%201.3)
or, RT = 1.3 units
Hence, the length between the two points is RT = 1.3 units
Answer:
8 inches
Step-by-step explanation:
Let w represent the width.
If the length is 14 inches longer than the width, it can be represented by w + 14.
Use the perimeter formula, p = 2l + 2w. Plug in 60 as the perimeter and w + 14 as l, then solve for w:
p = 2l + 2w
60 = 2(w + 14) + 2w
60 = 2w + 28 + 2w
60 = 4w + 28
32 = 4w
8 = w
So, the width is 8 inches
If you simplify it, it would be that same as 2/3.
If x is the high temperature, you can write the following equation:
x = 35°F + 13°F
Which simplifies to:
x = 48°F
Answer:
x = StartFraction negative
(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction
Step-by-step explanation:
0 = – 3x2 – 2x + 6
It can still be written as
– 3x2 – 2x + 6 =0
Quadratic formula=
-b+or-√b^2-4ac/2a
Where
a=-3
b=-2
c=6
x= -(-2)+ or-√(-2)^2-4(-3)(6)/2(-3)
x = StartFraction negative
(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction