Use these formulas to get the surface area and volume. Hopes this helps! ❤️
A horizontal shift would be in the form <span><span>f(x±k)</span></span>
Answer: AB is 15
Step-by-step explanation: First, you need to draw a picture and label the parts of the line: AB=5x-15; BC= 3x-5; AC =28. Because of the segment addition postulate, you set the equation to be 5x-15+3x-5=28. Then you solve:
5x-15+3x-5=28
Add like terms:
8x-20=28
Add 20 to both sides
8x=48
Divide by 8
x=6
Now, you need to find the measure of AB, so you plug the 6 into the x variable for 5x-15
5(6)-15
30-15
AB=15
Answer:
a) the probability that the minimum of the three is between 75 and 90 is 0.00072
b) the probability that the second smallest of the three is between 75 and 90 is 0.396
Step-by-step explanation:
Given that;
fx(x) = { 1/5 ; 50 < x < 100
0, otherwise}
Fx(x) = { x-50 / 50 ; 50 < x < 100
1 ; x > 100
a)
n = 3
F(1) (x) = nf(x) ( 1-F(x)^n-1
= 3 × 1/50 ( 1 - ((x-50)/50)²
= 3/50 (( 100 - x)/50)²
=3/50³ ( 100 - x)²
Therefore P ( 75 < (x) < 90) = ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx
= 3/50³ [ -2 (100 - x ]₇₅⁹⁰
= (3 ( -20 + 50)) / 50₃
= 9 / 12500 = 0.00072
b)
f(k) (x) = nf(x) ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k
Now for n = 3, k = 2
f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))
= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)
= 6/50³ ( 150x - x² - 5000 )
therefore
P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx
= 99 / 250 = 0.396
Answer:
The height of ball is 17 ft at t=0.55 and t=1.14.
Step-by-step explanation:
The general projectile motion is defined as
Where, v is initial velocity and y₀ is initial height.
It is given that the initial height is 7 and the initial upward velocity is 27.
Substitute v=27 and y₀=7 in the above equation to find the model for height of the ball.
The height of ball is 17 ft. Put h(t)=17.
On solving this equation using graphing calculator we get
Therefore the height of ball is 17 ft at t=0.55 and t=1.14.
