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Semenov [28]
3 years ago
8

How do you solve x^2 plus 16x plus 63=0?

Mathematics
1 answer:
Alex3 years ago
8 0
x^2+ 16x + 63=0 \\ \\a=1, \ b=16 , \ c=63 \\ \\ \Delta =b^2-4ac =16^2 -4\cdot1\cdot 63 = 256 -252 = 4 \\ \\x_{1}=\frac{-b-\Delta }{2a}=\frac{-16-\sqrt{4}}{2 }=\frac{-16-2}{2}=-\frac{-18}{2}=-9 \\ \\x_{2}=\frac{-b+\Delta }{2a}=\frac{-16+\sqrt{4}}{2 }=\frac{-16+2}{2}=-\frac{-14}{2}=-7 \\ \\ \\Answer : \ x= -7 \ \ or \ \ x= -9
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Answer:

Step-by-step explanation:x+y+z=100(let x ,y,z represent the first second and third numbers respectively)

Therefore,y=2z

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substituting the values of x,y and z into the question,we have

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Simplifying,we have

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adding 24 to both sides of the equation,

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4x=124

dividing both sides of the equation by the co-efficient of x,we have

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2 years ago
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