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Semenov [28]
3 years ago
8

How do you solve x^2 plus 16x plus 63=0?

Mathematics
1 answer:
Alex3 years ago
8 0
x^2+ 16x + 63=0 \\ \\a=1, \ b=16 , \ c=63 \\ \\ \Delta =b^2-4ac =16^2 -4\cdot1\cdot 63 = 256 -252 = 4 \\ \\x_{1}=\frac{-b-\Delta }{2a}=\frac{-16-\sqrt{4}}{2 }=\frac{-16-2}{2}=-\frac{-18}{2}=-9 \\ \\x_{2}=\frac{-b+\Delta }{2a}=\frac{-16+\sqrt{4}}{2 }=\frac{-16+2}{2}=-\frac{-14}{2}=-7 \\ \\ \\Answer : \ x= -7 \ \ or \ \ x= -9
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Answer:

a_{n}= 1+2n and 63

Step-by-step explanation:

the question belongs to arithmetic sequence and a_{n} can be determined by the formula

a_{n}= a1 + d (n-1)

Let " a_{n} " represents the number of band members in the nth row

and 'd' represents the common difference.( as stated each row  has 2 more band members than the row before it)

therefore, d=2

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->Rule for nth term will be:

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Let S_{n} represent total number in n rows

We'll use the formula, i.e  S_{n} = n/1 (a_{1} +  a_{n})

where, n is the number of terms, a_{1} is the first term and a_{n} is the last term

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n=7

a_{7} = 1 + 2(7)= 15

=>S_{7} = 7/2 (3 + 15)

S_{7} = 63

The total number of band members are 63

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