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3 years ago

HURRY Given f(x)=x^2−2x−5. Enter the quadratic function in vertex form in the box.

Mathematics

1 answer:

romanna [79]3 years ago

5 0

Answer:

$f(x)=(x-1)^2-6$

Step-by-step explanation:

The given quadratic function is

$f(x)=x^2-2x-5$

We complete the square to obtain the vertex form;

Add and subtract half the coefficient of $x$

$f(x)=x^2-2x+(-1)^2-(-1)^2-5$

Factor by identifying the perfect square

$f(x)=(x-1)^2-1-5$

Simplify to obtain the vertex form as

$f(x)=(x-1)^2-6$

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3 years ago

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$1)\text{ }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

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$\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}$ $N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

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1 year ago

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3 years ago

HURRY Given ​ f(x)=x^2−2x−5​. Enter the quadratic function in vertex form in the box.

HURRY Given f(x)=x^2−2x−5. Enter the quadratic function in vertex form in the box.