Answer:
See answer and graph below
Step-by-step explanation:
∬Ry2x2+y2dA
=∫Ry.2x.2+y.2dA
=A(2y+4Ryx)+c
=∫Ry.2x.2+y.2dA
Integral of a constant ∫pdx=px
=(2x+2.2Ryx)A
=A(2y+4Ryx)
=A(2y+4Ryx)+c
The graph of y=A(2y+4Ryx)+c assuming A=1 and c=2
Answer:
I think you would divide all of your numbers.
Step-by-step explanation:
13. 17y² - 22y
14. 9m²n+7mn²
15. 11y²
16. 8x²y
I'm not 100% sure if these are all correct, so please forgive me if I'm wrong.
Hopefully this helps, and please consider marking branliest.
Answer:
2.33 Seconds
Step-by-step explanation:
The equation y = -6t^2 - 10t + 56 expresses the height of a ball at a given time, t, on the planet Mars. We are also given that the ball is thrown with a velocity of 10 feet per second with the initial height of 56 feet.
To find the amount of time to reach the ground, we can say that the time being found will be when the ball is on the ground, or when y = 0. So we simply set our equation to 0 and solve for t.
y = -6t^2 - 10t + 56
0 = -6t^2 - 10t + 56
0 = -1 (6t^2 + 10t + -56)
0 = -1 (3t - 7) (2t + 8)
(3t - 7) = 0 OR (2t + 8) = 0
3t = 7 OR 2t = -8
t = 7/3 OR t = -4
Since time will not be negative, we will want to choose the positive solution for this quadratic equation.
Hence, the amount of time for the ball to hit the ground will be 7/3 seconds or 2.33 seconds.
Cheers.
The 200 parents. It basically means the amount/number of the population you are testing. In this case it would be the 200 parents.
