Answer:
0 ≤ t ≤ 5.
Step-by-step explanation:
In the function
,
is the independent variable. The domain of
is the set of all values of
that this function can accept.
In this case,
is defined in a real-life context. Hence, consider the real-life constraints on the two variables. Both time and volume should be non-negative. In other words,
.
.
The first condition is an inequality about
, which is indeed the independent variable.
However, the second condition is about
, the dependent variable of this function. It has to be rewritten as a condition about
.
.
Hence, t ≤ 5.
Combine the two inequalities to obtain the domain:
0 ≤ t ≤ 5.
Answer:
22
Step-by-step explanation:
198 = 2×3²×11
For 198n to be a perfect square, each prime factor must have an even exponent. So the smallest 198n would be:
198n = 2²×3²×11²
198n = 4356
n = 22
Answer:
The area of the rectangle is 12 cm² (to two significant figures)
Step-by-step explanation:
To determine the area of a rectangle that is 2.1-cm wide by 5.6-cm long,
The area of a rectangle is given by
Area = l × w
where l is the length
and w is the width
From the question,
l = 5.6 cm
and w = 2.1 cm
Hence, Area of the given rectangle will be
Area = 5.6 cm × 2.1 cm
Area = 11.76 cm²
Now, we will convert the answer to two significant figures
Then,
Area = 12 cm²
Hence, the area of the rectangle is 12 cm² (to two significant figures)
Step-by-step explanation:
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Answer:
-34b4
Step-by-step explanation:
Since the variables are the same b4, you just add the constants (-16 & -18).