You can get these points for free but I hope you would help at least 1 person on here and answer their problem.

Mathematics

2 answers:

nasty-shy [4]3 years ago

8 0

Answer:

Ty :)

Step-by-step explanation:

natali 33 [55]3 years ago

3 0

Answer:

Oh well I did today!

Step-by-step explanation:

Thanks for the free points they help a lot, I was struggling a lot today

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Plz help me I reaallllly neeed it plz Thank you I need to finish it Today

jek_recluse [69]

Picture please because I can’t help without a picture or something

6 0

3 years ago

The radius of a nitrogen atom is 5.8*10^-11 meters, and the radius of a beryllium atom is 1.12*10^-10 meters. Which atom has a l

Burka [1]

Nitrogen Radius = 5.8 x 10⁻¹¹ m

Beryllium Radius = 1.12 x 10⁻¹⁰ m

Let's find the quotient of N/Be :

(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1

→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.

Conclusion: the radius of Be is almost double than the radius of N

5 0

3 years ago

If g(x) = 3x + 1, evaluate g(-2).

zloy xaker [14]

G(x) = 3x + 1, evaluate g(-2).

Simply plug in (- 3) in g(x)

g(-2) = 3(-2) + 1

g(-2) = - 6 +1

g(-2) = - 5

4 0

3 years ago

Please Answer This Math Question? Here it is:; There was a typo thank you for saying that its Mrs. Gorski bought a table and 6 c

SCORPION-xisa [38]

So you'd do 980 - 524 = $456, and then 456 ÷ 6 = $76, which is the cost of 1 chair. We already know that 1 table is $524, so if you want 2 tables and 8 chairs you'd do (524 × 2) + (76 × 8), which is 1048 + 608 = $1656, which is your answer. I hope this helps!

6 0

3 years ago

when nancy started middle school, she was 60 inches tall. when she started high school, she was 66 inches tall. what was the per

Ivahew [28]

Answer:

The percent change in Nancy height is 10%

Step-by-step explanation:

Given : when Nancy started middle school, she was 60 inches tall. when she started high school, she was 66 inches tall.

We have to find the percent change in her height.

Percentage change is given by the ratio of the difference in old value and new value to the old value times 100

Mathematically written as

$Percentage\ change =\frac{new\ value-old\ value}{Old\ value}\times 100$