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kirill [66]
4 years ago
12

suppose a weather app says that the probability of rain today is 30%. What is the complement of the event ""rain today"" what is

the probability of the complement
Mathematics
1 answer:
ValentinkaMS [17]4 years ago
4 0

Answer:

The complement event would be: "No rain today"

Its probability would be 70%

Step-by-step explanation:

Given the event:

A= rain today

The probability of rain today is 30%

P(A)=30%=0.3

The complement event has all the values that are not included in the event.

The complement event would be:

A'= No rain today

The probability of a event is the subtraction between 1 and the complement event:

P(A')=1-P(A)

Then, the probability of the event "No rain today" will be:

P(A')=1-0.3=0.7=70%

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The equation for this is:

F = P(1+i)ⁿ
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i is the interest rate
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3 years ago
A forest has 800800800 pine trees, but a disease is introduced that kills \dfrac{1}{4} 4 1 ​ start fraction, 1, divided by, 4, e
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Respectively 3 / 4 should be the growth factor, starting with 800 pine trees - the start value. This can be represented as such,

P( t ) = a( b )^t - where a = start value, b = growth factor, t = time ( <em>variable quantity</em> )

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3 0
3 years ago
Erica sells bracelets for $2 each. The supplies to make each bracelet costs her $0.75. Let “n” represent the number of bracelet
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Answer:  1.25n

=======================================================

Explanation:

Erica sells bracelets for $2 each. If she makes and sells n of them, then she gets 2n dollars of revenue.

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Subtract the revenue and cost to get the profit

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3 years ago
Each square represents one square foot. Estimate the area of the figure below.
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7 0
3 years ago
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Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6
ElenaW [278]
<h2>Answer</h2>

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

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<h2>Explanation</h2>

Lets solve our system of equations  step by step

x^2+y^2=6 equation (1)

x^2-y=6 equation (2)

1. Solve for x^2 in equation (2)

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y(y+1)=0

y=0 or y=-1

3. Replace the values of y in equation (3) and solve for x

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x^2=6+y

x^2=6

x=\sqrt{6} or x=-\sqrt{6}

- For y=-1

x^2=6+y

x^2=6-1

x^2=5

x=\sqrt{5} or x=-\sqrt{5}

So, the solutions of our system of equation are:

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

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3 years ago
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