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bekas [8.4K]
2 years ago
8

A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collecte

d the following data based on a random sample of 100 days. Frequency Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100 Assuming that a goodness-of-fit test is to be conducted using a 0.10 level of significance, the critical value is:
Mathematics
1 answer:
allsm [11]2 years ago
5 0

Answer:

The degrees of freedom are given by;

df =n-1= 5-1=4

The significance level is 0.1 so then the critical value would be given by:

F_{cric}= 7.779

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

Step-by-step explanation:

For this case we have the following observed values:

Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100

For this case the expected values for each day are assumed:

E_i = \frac{100}{5}= 20

The statsitic would be given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}

Where O represent the observed values and E the expected values

The degrees of freedom are given by;

df =n-1= 5-1=4

The significance level is 0.1 so then the critical value would be given by:

F_{cric}= 7.779

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

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