Do this work if someone give correct answer I make her brainliest do this worksheet please

Katie received a speeding ticket that incurred a $125 fine. After one month, she will also

11Alexandr11 [23.1K]

Answer:

Try A

Step-by-step explanation:

3 0

2 years ago

Solve for x.<br> 10 m<br> 42

kramer

Answer:

The measures of a pair of same-side exterior angles are 10w and 5v. ... Find the measure of angles 1-7 given that lines m and n are parallel and t is transversal. ... Solve for x. 120= 15x +5+ 22x +4. 120 = 37% +. 4. (X=3]. 6. Use the following figure, given that ... Find the measure of angle 1. m24 = 123, mZ1 = 2x, mZ2 = x +42.

Step-by-step explanation:

5 0

2 years ago

Elena went to a sporting goods store that was having a sale. She bought a tennis ball and 3 cans of tenis balls The tennis racke

Kazeer [188]

Answer: She will pay $52.68, including taxes

Step-by-step explanation: One can of tennis ball is $4 and there are no discount on it. Elena bought 3 cans, so:

can = 3 x 4 = 12

One tennis racket is $43 but it has a discount of 15%:

discount = 0.15 x 43 = 6.45

total racket = 43 - 6.45 = 36.55

Elena will have to pay:

pay = 12 + 36.55 = 48.55

She will also have to pay taxes, which are 8.5% over the price she paid:

pay + tax = 48.55 x 0.085 = 4.13

total to pay = 48.55 + 4.13 = 52.68

Buying 3 can of tennins ball and one racket, Elena paid $52.68, including taxes.

4 0

3 years ago

Use the menu provided to answer the following question. If a student purchased 1 can of juice, 2 slices of pizza, 1 bag of peanu

pochemuha

Answer:

$8.25

Step-by-step explanation:

1.25+(2.25x2)+1.00+(1.25x2)=8.25

3 0

2 years ago

Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th

Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

$P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312$

Probability of having an emergency locator and not being discovered:

20% of 28%. So

$P(A cap B) = 0.2*0.28 = 0.056$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105$

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

$P(A) = 1 - 0.5312 = 0.4688$

Probability of not having an emergency locator and being discovered:

34% of 72%. So

$P(A \cap B) = 0.34*0.72 = 0.2448$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522$

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

$P(A \cap B) = 0.66*0.72 = 0.4752$

Probability of being discovered, given that it has the emergency recorder:

$p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946$

This question asks for P(X = 7) when $n = 10$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064$

0.064 = 6.4% probability that 7 of them are discovered.

8 0

2 years ago