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JulsSmile [24]
3 years ago
10

Do this work if someone give correct answer I make her brainliest do this worksheet please

Mathematics
1 answer:
AfilCa [17]3 years ago
7 0

Answer:

I hope my answers are correct!

Hope thai helps!

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1. The cost of petrol rises by 2 cents a liter. last week a man bought 20 liters at the old price. This week he bought 10 liters
AnnyKZ [126]
Answer for #1


Let the old price be
$
x
per liter. 10 liters would have cost a total of
$
10
x
.

The new price is
$
(
x
+
0.20
)
per liter. 10 liters would have cost
$
10
(
x
+
0.20
)
.

The total cost is
$
9.20
. So,



10
x
+
10
(
x
+
0.20
)
=
9.20
10
x
+
10
x
=
9.20
−
2
x
=
7.20
20
x
=
0.36




Thus, the old price was
$
0.36
per liter.
8 0
3 years ago
I really need this A circle with radius 16 cm has a segment with a central angle of 90 . What is the area of the segment?​
Darya [45]
A= r2•a / 2
Central angle 90°
Radius 16 cm
Diameter 32cm
Sector Area 201 cm2
Arc Length 25.13cm
Chord Length 22.63cm


Hope this helps!!
8 0
3 years ago
In a jar there are 3 yellow candies, 3 blue candies, and 2 orange candies. What percent of the jar is filled with orange candies
Nastasia [14]

Answer: 25 percent of the jar is filled with orange candies

Step-by-step explanation:

In the jar, there are 3 yellow candies, 3 blue candies, and 2 orange candies. This means that the total number of candies inside the jar would be the sum of the yellow, blue and orange candies. It becomes

3 + 3 + 2 = 8 candies.

The percent of the jar filled with orange candies would be expressed as

number of orange candies/total number of candies × 100

It becomes

2/8 × 100 = 25%

4 0
3 years ago
Select the correct answer.<br> Rewrite the following equation as a function of x.
ivolga24 [154]

Option B:

${f(x)}=9280-20x

Solution:

$\frac{1}{16} x+\frac{1}{320} y-29=0

$\frac{1}{16} x+\frac{1}{320} y-\frac{29}{1} =0

Take LCM of the denominators and Make the denominators same.

LCM of 16, 320, 1 = 320

$\frac{1\times20}{16\times20} x+\frac{1}{320} y-\frac{29\times 320}{1\times 320} =0

$\frac{20}{320} x+\frac{1}{320} y-\frac{9280}{320} =0

All the denominators are same, so you can write in one fraction.

$\frac{20x+y-9280}{320}=0

Do cross multiplication.

${20x+y-9280}=0\times 320

${20x+y-9280}=0

Add 9280 on both sides of the equation.

${20x+y}=9280

Subtract 20x on both sides of the equation.

${y}=9280-20x

Let y = f(x).

${f(x)}=9280-20x

Hence Option B is the correct answer.

6 0
4 years ago
Solve each system by substitution<br><br> 2x - 3y = -1<br> X + 4y = -6
lord [1]

Answer:

(- 2, - 1 )

Step-by-step explanation:

Given the 2 equations

2x - 3y = - 1 → (1)

x + 4y = - 6 → (2)

Rearrange (2) expressing x in terms of y by subtracting 4y from both sides

x = - 6 - 4y → (3)

Substitute x = - 6 - 4y into (1)

2(- 6 - 4y) - 3y = - 1 ← distribute and simplify left side

- 12 - 8y - 3y = - 1

- 12 - 11y = - 1 ( add 12 to both sides )

- 11y = 11 ( divide both sides by - 11 )

y = - 1

Substitute y = - 1 into (3) for corresponding value of x

x = - 6 - 4(- 1) = - 6 + 4 = - 2

Solution is (- 2, - 1 )

3 0
3 years ago
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