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3 years ago

What is the slope of the line that passes through (5,-4) and (2,2)

Mathematics

2 answers:

maxonik [38]3 years ago

4 0

The slope of this line is -2

julia-pushkina [17]3 years ago

4 0

The answer is -2 because that is the slope that passes through (5,-4) and (2,2)

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Will give brainliest if u help

WARRIOR [948]

Answer:

1. the translation from the original to the translated figure was 2 units up and 1 unit to the left

2. the points of the translated figure if it were translated 2 units down and 3 units to the right would be: A' (4,0), B' (6,-6), C' (5,3), D' (-1,0)

Step-by-step explanation:

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3 years ago

15 POINTS!!!<br> Please help me and write a response! ^v^ thank you!

Blababa [14]

Answer:

see below

Step-by-step explanation:

When we add fractions with the same denominator (bottom), we do not add the denominator, we keep it the same. We only add the numerator (top)

1/2 + 1/2 = 2/2 =1

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3 years ago

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mrs.cashmore bought a large melon. She cut a piece that weighed 1 1/8 pounds and gave it to her neighbor. The remaining piece of

madreJ [45]

The answer is 1 7/8 pounds

7 0

3 years ago

Read 2 more answers

What is the antiderivative of 3x/((x-1)^2)

Maslowich

Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

Given

$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx$

$=3\cdot \int \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Apply\:u-substitution:}\:u=x-1$

$=3\cdot \int \frac{u+1}{u^2}du$

$\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}$

$=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)$

$\int \frac{1}{u}du=\ln \left|u\right|$ ∵ $\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)$

$\int \frac{1}{u^2}du=-\frac{1}{u}$ ∵ $\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=3\left(\ln \left|u\right|-\frac{1}{u}\right)$

$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Therefore,

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

4 0

3 years ago

The table shows the relationship of how many pounds of cherries are needed to make a certain number of pies:

posledela

Answer:

C. A graph is drawn. The horizontal axis and vertical axis values are 0 to 70 in increments of 10. The horizontal axis label is Number of Pies, and the vertical axis label is Pounds of Cherries. Points are plotted on the ordered pairs 30, 20 and 45, 30 and 60, 40.

Step-by-step explanation:

If we take two of the original points from the data and put them in to two point form we get the following equation.

(6,4) and (12,8)

(y-4) = [(8-4)/(12-6)](x-6)

y = 2/3x

You have to start a the origin since we can only have enough ingredients to make pies and we can't start with partial pies. So move to y intercept up by 2.

Put the x values in for answer C and you'll return the y values.

6 0

3 years ago