Find the fourth roots of 256(cos 240° + i sin 240°).

Mathematics

1 answer:

Mashcka [7]2 years ago

8 0

Answer with Step-by-step explanation:

We are given that

We have to find the fourth roots of given complex number.

$(256)^{\frac{1}{4}}=(4^4)^{\frac{1}{4}}=4^^{\frac{1}{4}\times 4}=4$

By using the formula

$(a^b)^x=a^{bx}$

$\theta=240^{\circ}$

$\theta=\frac{240}{4}=60^{\circ}$

Angle of rotation= $\frac{360}{4}=90^{\circ}$

Therefore, the four roots of given complex number are

$4(cos 60^{\circ}+i sin60^{\circ})$

$4(cos150^{\circ}+i sin150^{\circ})$

$4(cos240^{\circ}+isin 240^{\circ})$

$4(cos330^{\circ}+i sin330^{\circ})$

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Which fraction is less than 1 chose all of the correct answer, and explain why you chose and write it down and explain your answ

EleoNora [17]

Answer:

$(3/4)$ and $(2/3)$ .

Step-by-step explanation:

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$\begin{aligned} \frac{p}{q} \quad \genfrac{}{}{0}{}{(\text{numerator})}{(\text{denominator})}\end{aligned}$ .

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For example, in the fraction $(2/3)$ , $2$ is the numerator while $3$ is the denominator. Both the numerator and the denominator are positive, while the numerator $2\!$ is smaller than the denominator $3\!$ . Therefore, $(2/3)$ would be less than $1$ .