The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at
(-1.5, -3.25).
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For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
Answer:
exact form 3/2 decimal form 1.5 mixed number form 1 1/2
Step-by-step explanation:
Correct. Two congruent triangles are formed.
The two triangles are congruent because
1. diagonal = common side between two triangles
2. Considering the diagonal as a transversal that cuts the two pairs of parallel lines, we have two sets of internal alternate angles.
BY the rule of ASA, the two triangles are congruent.
4x + 3y = 9
4x - 4x + 3y = -4x + 9
3y = -4x + 9
3 3
y = -1¹/₃x + 3
Answer:
mu = x√P(x) - £
£ = x√P(x) - xP(x)
Step-by-step explanation:
We have two equations there. Laying them simultaneously, we can derive the formula for "mu" and sigma. Let sigma be "£"
Equation 1
mu = £[xP(x)]
Equation 2
£^2 = x^2 P(x) - (mu)^2
Since we have sigma raised to power 2 (that is sigma square), we find sigma by square rooting the whole equation.
Hence sigma is equal to
[x√P(x) - mu] ...(3)
Since mu = xP(x), we substitute this into equation (3) to get
Sigma = x√P(x) - xP(x)
mu = x√P(x) - £
