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mart [117]
3 years ago
12

The hypotenuse of a right triangle has length 50 cm. One leg has length 20 cm. The nearest tenth, what is the length of the othe

r leg?​
Mathematics
1 answer:
Fantom [35]3 years ago
6 0

Answer:

45.8 cm

Step-by-step explanation:

Let the length of other leg be l

By pythagoras theorem,

l \:  =  \sqrt{ {50}^{2} -  {20}^{2}  }  \\ l \:  = 45.8cm

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Answer:

-14

Step-by-step explanation:

First of all, we know that 5x^2+ ax+7x +5=0 only has one root. That means that b^2 - 4ac=0, and we can use this to find the discriminant, ax + 7x.

Now, if we simplified 5x^2+ ax+7x +5=0, by dividing it all by 5, it would be x^2+(a+7)/5x + 1 = 0.

After, we can plug what we know into the formula, b^2 - 4ac=0. It would be:

(a+7)^2 / 25 - 4 = 0

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Since this is a square root, a+7 can be both negative or positive.

a+7= 10, or a+7 = -10

a=3, or a=-17

The question asks for the sum of a, which is 3 + (-17) = -14

Therefore, the answer is -14.

:) have fun with your rsm problems, assuming you got this from the portal.

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3 years ago
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