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Whitepunk [10]
3 years ago
11

A complete table with values for x or y that make this equation true:3x+y=15

Mathematics
1 answer:
Reika [66]3 years ago
8 0

Answer:

Table is attached

Step-by-step explanation:

We are given equation as

3x+y=15

We will complete each column

First column:

we are given x=2 and we have to find y

3\times 2+y=15

6+y=15

y=9

Second column:

we are given y=3 and we have to find x

3x+3=15

3x=12

x=4

Third column:

we are given x=6 and we have to find y

3\times 6+y=15

18+y=12

y=-6

Fourth column:

we are given x=0 and we have to find y

3\times 0+y=15

0+y=15

y=15

Fifth column:

we are given x=3 and we have to find y

3\times 3+y=15

9+y=15

y=6

Sixth column:

we are given y=0 and we have to find x

3x+0=15

3x=15

x=5

Seventh column:

we are given y=8 and we have to find x

3x+8=15

3x=7

x=\frac{7}{3}

now, we can complete table



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Which of the following is a rational number?​
scoray [572]

Examples of rational numbers are: -2 = -2/1, -5 = -5/1, -14 = -14/1, 1/2, 2/3, 5/8, 3/4, 17/5, . 6 = 6/10 = 3/5, . 25 = 1/4, . 33 = 33/100, 2¾ = 11/4, 3⅓ = 10/3, .
5 0
3 years ago
A company purchased $10,000 of merchandise on January 5 with terms 2/10, n/30. On January 7, it returned $1,200 worth of merchan
s2008m [1.1K]

Answer:

C. Debit Accounts Payable $8,800; credit Merchandise Inventory, $176; credit Cash $8,624.

Step-by-step explanation:

Data given in the question is inconsistent with the options given.

Terms 2/10, n/30 means there is a discount of 2% is available on payment of due amount within discount period of 10 days after sale with net credit period of 30 days.

Purchases = $10,000

Returns = $1,200

Amount Due = $10,000 - $1,200 = $8,800

As the payment is made after discount period, so no discount will be availed. Full amount of $8,800 will be paid.

A similar and correct question is given below and answer is made accordingly.

A company purchased $10,000 of merchandise on January 5 with terms 2/10, n/30. On January 7, it returned $1,200 worth of merchandise. On January 12, it paid the full amount due. Assuming the company uses a perpetual inventory system, and records purchases using the gross method, the correct journal entry to record the payment on January 12 is:

Debit Accounts Payable $10,000; credit Merchandise Inventory $200; credit Cash $9,800.

Debit Merchandise Inventory $8,800; credit Cash $8,800.

Debit Accounts Payable $8,800; credit Merchandise Inventory, $176; credit Cash $8,624.

Debit Cash $1,600; credit Accounts Payable $1,600.

Debit Accounts Payable $8,624; credit Cash $8,624.

Solution

Terms 2/10, n/30 means there is a discount of 2% is available on payment of due amount within discount period of 10 days after sale with net credit period of 30 days.

Purchases = $10,000

Returns = $1,200

Amount Due = $10,000 - $1,200 = $8,800

As the payment is made within discount period, so discount will be availed

Discount = $8,800 x 2% = $176

Cash Paid = $8,800 - $176 = $8,624

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3 years ago
Find the slope and y intercept 2x+3y=1,470
oksano4ka [1.4K]
First we need to put it in slope intercept form (solve for y). Then we get tex]y= -\frac{2}{3} x+490[/tex]. So the slope is-2/3 and the y intercept is 490.
8 0
3 years ago
Read 2 more answers
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
wesley. is very particular about his salad He must have 10 leaves of lettuce for every 4 pieces of carrots If he has 50 leaves o
tatyana61 [14]

Answer:

20 carrots

Step-by-step explanation:

4/10

x/50

10 x 5 = 50

4 x 5 = x

x = 20

20/50

7 0
3 years ago
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