There are several information's already given in the question. Lat us first write them down and then go for solving the problem.
Total number of pupil <span>in Secondary one = 225
Let us assume the number of pupil who do not pay the school fees through GIRO scheme = x
Then
Number </span>of pupil who pay the school fees through GIRO scheme = 14x
So
x + 14x = 225
15x = 225
x = 15
From the above deduction, it can be concluded that 15 pupil did not join the scheme.
Answer: segment KH
Explanation:
The altitude of a triangle is defined as a segment connecting one of the vertex of the triangle with the opposite side of the triangle (or with an external prolongation of it), forming a right angle with it.
Note that the altitude of a triangle can also be outside the area of the triangle.
If we look at the picture, we see that:
- IH is a side, so it is not an altitude of the triangle
- KH is an altitude of the triangle, since it connects the vertex H with the external prolongation of IG, and it makes a right angle with it
- GJ: we don't know if it is an altitude, since we don't know if it forms a right angle or not
- GH: it is a side of the triangle, so it is not an altitude
So, the correct answer is segment KH.
Area of sector=fraction of sector times area of circle
fraction of sector=degrees/360
and area of circle=pir^2
so
hold a sec, we have the wiper on the outside, so we want to find the outside ring thing
do
area big sector-area small sector
or even better
(degrees/360) times (area big-areasmall)
big is 10
small is 4 (10-6=4)
areabig=10^2 times pi or 100pi
areasmall=4^2 times pi or 16pi
areabig-areasmall=100pi-16pi=84pi
then find the fraction
84pi times (150/360)=35pi square inches
The expression to evaluate is 32 + (8 - 2) * 4 - 6/3.
In the first step you can solve the parenthesis and the fraction => 32 + (6)*4 - 2.
In the second step you mutiply 6*4 => 32 + 24 - 2.
Finally, you do the maths: 32 + 24 - 2 = 54.
<span>Answer: 54</span>
The result of simplifying the expression (x²/x⁻¹¹)¹/₃ using the exponent rules is ![\sqrt[3]{}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D)
(x¹³)
To solve this exercise we have to resolve algebraic operations following the exponent rules.
(x²/x⁻¹¹)¹/₃
Using the quotient rule that indicates that: the exponent result will be the subtraction of these exponents, we have:
(x⁽²⁻⁽⁻¹¹⁾)¹/₃
(x⁽²⁺¹¹⁾)¹/₃
(x¹³)¹/₃
Using the power of a power rule that indicates that: the exponent result will be the multiplication of these powers, we have:
x⁽¹³*¹/₃⁾
x⁽¹³/₃⁾
As we have a fractional exponent, you must convert the exponent to root:
(x¹³)
<h3>What is an exponent?</h3>
In mathematics an exponent is the number of time that a number, called (base) is multiplied by itself. It is also called, power or index.
Example: 3² = 3*3 = 9
Learn more about exponent at: brainly.com/question/847241
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