The second one because it allows for all the points to be presented
Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:
Likewise:
Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:
Likewise:
Since ∠QAC ≅ ∠PAB:
And by substitution:
Thus:
Then by SAS Congruence:
And by CPCTC:
Answer:
B. y = -x - 1
Step-by-step explanation:
Perpendicular lines have opposite reciprocal slopes, so the slope of the new line will be -1.
Plug the slope and the given point into y = mx + b to find b:
y = mx + b
3 = -1(-4) + b
3 = 4 + b
-1 = b
Then, plug this and the slope into y = mx + b
y = -x - 1
So, the correct answer is B, y = -x - 1
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Answer:
7x-2 = 12x-22
-7x
-2=5x-22
+22
20=5x
÷5
x=4
KL is 7x-2, so substitute the value of x.
7 x 4 - 2 = 26
KL = 26
Hope this helps!
