The answr is A sorry if wrong
<u>Given</u>:
Given that FGH is a right triangle. The sine of angle F is 0.53.
We need to determine the cosine of angle H.
<u>Cosine of angle H:</u>
Given that the sine of angle F is 0.53
This can be written as,

Applying the trigonometric ratio, we have;
----- (1)
Now, we shall determine the value of cosine of angle H.
Let us apply the trigonometric ratio
, we get;
----- (2)
Substituting the value from equation (1) in equation (2), we get;

Thus, the cosine of angle H is 0.53
Answer:
Step-by-step explanation:
<u>As per diagram:</u>
- ∠NXY ≅ ∠XYZ as alternate interior angles since XN and YN are parallel and XY is transversal
- m∠XYZ = m∠XZY = 63° since ΔXYZ is isosceles
<u>Find the measure of ∠YXZ:</u>
- m∠YXZ = 180° - 2*63° = 54°
<u>Find the bearing of Z from X:</u>
- m∠NXZ = m∠NXY + m∠YXZ = 63° + 54° = 117°
Answer:
2
Step-by-step explanation: