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notsponge [240]
4 years ago
14

How can I write 625 in as many ways as I can in exponents

Mathematics
1 answer:
kirill [66]4 years ago
4 0

Well,  625  is  5 x 5 x 5 x 5 .

So that would be:

(5)⁴

5 x (5)³

(5)² x (5)²

And you could even go the other way if you want to get silly:

(5)⁵ x (5)⁻¹

(5)⁶ x (5)⁻²
.
.
etc.

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Solve -4x – 8y = -48<br> 8x + 3y = -34.
Likurg_2 [28]

Answer:

x= -1/2 and -32

y = -10

Step-by-step explanation:

1) 2(-4x-8y)= (-48)2

8x+3y =-34

*to create a way to cancel out the x*

2) -8x-16y= -96

8x+3y= -34

*add them

-8x +8x =0

-16y + 3y = -13y

-96+ -34= -130

3) -13y =-130

isolate y

4) y = -10

*plug in* to find x into both original equations*

5) 8x + 3(-10) = -34. -4x-8(-10)= -48

*follow order of operations to solve for x

6) 8x -30 =-34. -4x +80 = -48

7) 8x =-4. -4x =128

8) x= -1/2. x = -32

4 0
3 years ago
What is the horizontal distance between (−5/3, -2) and (4, -2)?
Nataly [62]

Answer:

-2?

Step-by-step explanation:

use y2-y1 over x2-x1 to find the answer. So you would do -2--5/3 over 4--2. The two negitives turn into a positive. SO it is now -2+5/3 over 4+2. -2+5/3= -1/3 over 4+2=6 it is now -1/3/6 which equals -2. So I think the answer is -2.<u> I do not know if you should trust me on this but I tried. </u>

6 0
3 years ago
A parent died and left an estate to four children. One inherited
svetoff [14.1K]
1-0.5-0.125-0.25= 1-0.875=0.125
3 0
3 years ago
Math questions, pls help me and ill reward &lt;3 : )
EastWind [94]

Answer:

X = 6

Step-by-step explanation:

See Attachment

5 0
3 years ago
Write the equation in standard form. Identity the center and radius.<br> x² + y2 + 8x-4y-7=0
lorasvet [3.4K]

Answer:

equation;

(x + 4) {}^{2}  + (y - 2) {}^{2}  = 27

Center (-4,2)

Radius is

3 \sqrt{3}

Step-by-step explanation:

Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

(x - h) {}^{2}  + (y - k)  {}^{2}  =  {r}^{2}

Where (h,k) is center

r is the radius

So first we group like Terms together

{x}^{2}  + 8x  +  {y}^{2}  - 4y - 7 = 0

Add 7 to both sides

{x}^{2}  + 8x +  {y}^{2}  - 4y = 7

( {x}^{2}  + 8x) +(  {y}^{2}  - 4y) = 7

Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

(\frac{8}{2} ) {}^{2}  = 16

and

( - \frac{4}{2} ) {}^{2}  = 4

so we have

{x}^{2}  + 8x + 16 +  {y}^{2}  - 4y + 4y = 7 + 16 + 4

{x}^{2}  + 8x + 16  +  {y}^{2}  - 4y + 4y = 27

(x + 4) {}^{2}  +  (y  - 2) {}^{2}  = 27

To find our center, h is -4 and k is 2

so the center is (-4,2)

The radius is

\sqrt{27}  = 3 \sqrt{3}

So the radius is 3 times sqr root of 3.

8 0
2 years ago
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