If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)
equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)
So, option D is correct
Answer:
x=24
Step-by-step explanation:
The Quotient(dividing) of a number(x) and 6 minus(-) 3 IS(=) 1.
Which turns into:
- 3 = 1
We want to get x by itself so we divide the entire equation by 6.
6 ( - 3 = 1 )
x - 18 = 6
We want to move the plain numbers to one side so x can be by itself. So we add 18 to both sides.
x = 24
Answer:I think the answer is multiplication property of equality
Step-by-step explanation:
it is being multiplied to get the answer so that should be the answer
Answer:
<em>x </em>= -2
<em>y </em>= 0
Step-by-step explanation:
Pretty hard process, but let me explain:
First, solve for y.
Substitute -x - 2 for y in x - y = -2:
Then, simplify both sides of the equation.
x - y = -2
x - (-x - 2) = -2
After, add -2 to both sides of the equation.
2x + 2 = -2
2x + 2 + -2 = -2 + -2
Next, divided both sides by 2.
2x/2 = -4/2
After that, substitute -2 for x in y = -x - 2:
You must simplify both sides of the equation.
y = -x - 2
y = -(-2) - 2
y = 0
Sorry if this is long and confusing, but I hope this helps!!
I swear if it’s wrong I’m sorry ok but it’s 3 for me
