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3 years ago

What is this equation? -4b^2-6b-10

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

5 0

C is the answer to the question.
As the equation is the form y= ax^2 + bx + c

Gre4nikov [31]3 years ago

5 0

C. Quadratic Trinomial

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I am a 2 digit number.

AlexFokin [52]

Answer:

Step-by-step explanation:

6+5=11

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3 years ago

Factor by finding the GCF:<br> 8x-10

lys-0071 [83]

Answer:

The GCF is 2

Step-by-step explanation:

Hope this helps!!

3 0

3 years ago

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How does the graph of the function g(x) = 2x – 4 differ from the graph of f(x) = 2x

Lena [83]

9514 1404 393

Answer:

the y-intercepts differ

Step-by-step explanation:

The x-coefficient is the same for each function, so parallel lines are described. The function g(x) has a y-intercept of -4; f(x) has a y-intercept of 0.

The graphs differ in their intercepts.

<em>Additional comment</em>

g(x) can be considered to be a translation downward of f(x) by 4 units. The same graph of g(x) can be obtained by translating f(x) to the right by 2 units. That is, both the x-intercepts and y-intercepts differ between the two functions.

5 0

2 years ago

True or False:

atroni [7]

Answer:

no it can't because

Step-by-step explanation:

coz the sum of any two angle should be greater than 3rd side

13 + 5 = 18 which is greater than 7
13 + 7 = 20 which is greater than 5
5 + 7 = 12 which is not greater than 13

so triangle cant be made

3 0

3 years ago

What is the equation of the line that is perpendicular to y= -3x + 1 and passes through (2,3)?

Aleonysh [2.5K]

Answer:

$\large\boxed{y=\dfrac{1}{3}x+2\dfrac{1}{3}}$

Step-by-step explanation:

$\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=-3x+1\to m_1=-3.\\\\\text{Therefore}\ m_2=-\dfrac{1}{-3}=\dfrac{1}{3}.\\\\\text{The equation of the searched line:}\ y=\dfrac{1}{3}x+b.\\\\\text{The line passes through }(2,\ 3).$

$\text{Put the coordinates of the point to the equation.}\ x=2,\ y=3:\\\\3=\dfrac{1}{3}(2)+b\\\\3=\dfrac{2}{3}+b\qquad\text{subtract}\ \dfrac{2}{3}\ \text{from both sides}\\\\b=2\dfrac{1}{3}$

3 0

3 years ago

Read 2 more answers