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boyakko [2]
3 years ago
11

Ng the Zero Product Property Warm-Up Which are solutions of the equation (x + 5)(x-3) = 0?

Mathematics
1 answer:
Leto [7]3 years ago
7 0

For this case we have a factorized quadratic equation. We equal each factor to zero and thus find the roots:

x + 5 = 0

Subtracting 5 from both sides we have:

x = -5

Thus, the first solution of the equation is:

x_ {1} = - 5

On the other hand we have:

x-3 = 0

Adding 3 to both sides:

x = 3

Thus, the second solution of the equation is:

x_ {2} = 3

Answer:

The solutions of the equation are:

x_ {1} = - 5\\x_ {2} = 3

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\large\boxed{\text{70 seconds}}

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Explanation:


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t = \text{time for the auditor to finish his work } = 720 \text{ seconds}&#10;\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}&#10;\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

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P(t \ \textgreater \  720) &#10;\\ = P(z \ \textgreater \  1.2)&#10;\\ = 1 - P(z \leq 1.2)&#10;\\ = 1 - 0.885&#10;\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

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