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3 years ago

I don't know how to do this number6

Mathematics

1 answer:

Ede4ka [16]3 years ago

5 0

Ben got the five and the six mixed up in the report. He can fix this by writing 5,650,000 instead.

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Helpp me answer this question and explain

Ganezh [65]

The answer is A, you can tell because if you multiply 4 by the numbers inside the parentheses you’ll get =12+24..hope that helped :)

4 0

3 years ago

In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?

snow_lady [41]

If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB

Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°

Next, look at ΔADB. ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°

Now look at ΔADC. Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC per angle addition postulate.

Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.

CD = 4 cm (given) so AC = 2(4 cm) = 8 cm

Since AC ≅ BC, then BC = 8 cm. Therefore, BD = 4 + 8 = 12 by segment addition postulate.

Lastly, look at ΔBHD. Since ∠B = 30° and ∠H = 90°, then ∠D = 60°. So, ΔBHD is also a 30-60-90 triangle.

BD = 12 cm, so HD = $\frac{12}{2}cm$ = 6 cm

Answer: 6 cm

8 0

3 years ago

Read 2 more answers

A new bank account is opened on week 1 with a $200 deposit. After that first week, weekly deposits of $55 are made in the accoun

inysia [295]

Y=55x+200, you multiply the number of weeks by the amount of money, and add 200 because they started with that.

7 0

3 years ago

Read 2 more answers

Plz help me !!!!!!!!!!!

liberstina [14]

Answer: a) -240

Step-by-step explanation:

$2\sqrt{-32}\cdot 5\sqrt{-18}\\\\=2\cdot 5\sqrt{-32\cdot -18}\\\\=10\sqrt{-1\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot -1\cdot 2\cdot 3\cdot 3}\\\\\\=10(-1\cdot 2\cdot 2\cdot 2\cdot 3)\\\\=10(-24)\\\\=\boxed{-240}$

4 0

4 years ago

Find p(0),p(1),p(-1) and p(2) of the 3x(x-2)

Effectus [21]

Answer:

make x→0

$p(0)=(0)^{2}-3(0)+2$

→ $p(0)=0+0+2$

→ $p(0)=2$

$------$

Replace x→-1

$p(-1)=(-1) ^{2} -3 (-1)+2$

→ $p(-1)=1-3+2$

→ $p(-1)=0$

$----------$

Now make x→2

$p(2)=(2) ^{2} -3(2)+2$

→ $p(2)=4-6+2$

→ $p(2)=0$

$Answer:-2,0,0$

$-----------$

hope it helps...

have a great day!!

5 0

3 years ago