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3 years ago

I don't know how to do this number6

Mathematics

1 answer:

Ede4ka [16]3 years ago

5 0

Ben got the five and the six mixed up in the report. He can fix this by writing 5,650,000 instead.

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Tyrone and Trish have coin collections. Tyrone starts with 152 coins, and Trish starts with 200. Each week, Tyrone adds 10 coins

madam [21]

what's the question?

4 0

3 years ago

Solve the equation 3(4 + 3r)

sertanlavr [38]

The answer is 12+3r because 4 times 3=12 then the 3r which you cannot add because they are no others variables that are r

5 0

3 years ago

Vince has a rectangular rug in his room with an area of 10 ft the length of the rug is 18 inches longer than the width what coul

aev [14]

The length of the rug is 4 ft.

The width of the rug is 2.5 ft.

Explanation:

The area of the rug is 10 ft.

The length of the rug be l.

Let us convert the inches to feet.

Thus, $18 inches = 1.5 ft$

Thus, the length of the rug is $l=1.5+w$

Let the width of the rug be w.

Substituting these values in the formula of area of the rectangle, we get,

$A=length\times width$

$10=(1.5+w)(w)\\10=1.5w+w^2\\w^2+1.5w-10=0$

Solving the expression using the quadratic formula,

$w=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Substituting the values, we have,

$$w=\frac{-15 \pm \sqrt{15^{2}-4 \cdot 10(-100)}}{2 \cdot 10}\\$

$w=\frac{-15 \pm \sqrt{4225}}{20}$

$w=\frac{-15 \pm 65}{2 0}$

Thus,

$w=\frac{-15 + 65}{2 0}\\w=\frac{50}{20} \\w=2.5$ and $w=\frac{-15 - 65}{2 0}\\w=\frac{-80}{20} \\w=-4$

Since, the value of w cannot be negative, the value of w is 2.5ft

Thus, the width of the rug is 2.5ft

Substituting $w=2.5$ in $l=1.5+w$ , we get,

$l=1.5+2.5\\l=4$

Thus, the length of the rug is 4 ft.

4 0

3 years ago

The sum of two numbers is 52. The larger number is 8 more than the smaller number. What are the numbers?

iVinArrow [24]

Answer:

The smaller number is 22

The larger number is 30

Step-by-step explanation:

L + S = 52

L = S + 8

Set both equations equal to L.

S + 8 = -S + 52

+S +S

2S + 8 = 52

- 8 - 8

2S = 44

S = 22

To find the larger number, plug 22 in as S into the equations.

L = 30

3 0

3 years ago

43 coins, no nickels, $4.51 equal amount amount of pennies and dimes, how many of each coin

Sonbull [250]

Set up
Let the dimes = d
Let the pennies = p
Let the quarters = q

Equations
You cannot mean that the pennies and dimes have equal numbers. That would mean that each had 21.5 members. Now could you mean that the dime and penny amount could be the same with 43 coins that total 4.00. Four dollars means that you need 40 dimes alone. It must mean that you are including quarters.

p + d + p = 43 (1)
p = d (2)
p +10d +25q = 451 (3)

Note how this last equation = was derived. You have to multiply the dimes by 10 and he quarters by 100 and the total by 100 to get the numbers all in pennies.

Put the results of 2 into 1.
2p + q = 43 (4)
You need to modify equation 3 as well.
p + 10p + 25q = 451
11p + 25q = 451 (5)

Solve the new equations
2p + q = 43 (4)
11p + 25q = 451 (5)

Multiply 4 by 25
25(2p- + q = 43)
50p + 25q = 1075 (6) Subtract (5) from (6)
<u>11p + 25q = 451
</u>39p = 624 Divide by 39
p = 624 / 39
p = 16

Since the pennies and dimes are equal there are 16 dimes
p + d + q = 43
16 + 16 + q = 43
32 + q = 43
q = 11

Check
16 + 10*16 + 11*25 = ?
16 + 160 + 275 = ?
451 = ?

Nice problem. Thanks for posting.

3 0

3 years ago