263.25 is the volume of the box in inches cubes you have to multiply 4.5 by 9 by 6.5
Answer:
5/3 = z
Step-by-step explanation:
You can use proportions to figure this out.
Imma solve this as I work through it.
So
4/z is equal to 12/5. So you can do something called the butterfly method (I have never used this before, but it works tho) and the method involves only multiplication and division.
Lemme clean this up for ya
The butterfly method involves multiplying in a cross format on both sides, so the
4 12
__ = ______
z 5
becomes 4 times 5, and z times 12.
4 times 5 is 20, and z times 12 is 12z
so you now have 20 = 12z
Lets simplify the equation by dividing by 4s
20 divided by 4 is 5 and 12z divided by 4 is 3z
so
5 = 3z
You can divide again
by dividing both sides
by
3
to get the unit rate of z.
It will be a fraction though
and it won't look pretty
but here it is:
5
__ = z
3
So
It is
5/3
Hope this helps
and hope you get a laugh out of this
yeeha
Answer:
She is 11.25 years old.
Step-by-step explanation:
I just did 45 divided by 4.
Answer:
Matrix multiplication is not conmutative
Step-by-step explanation:
The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix
Let A with dimension mxn and B with dimension nxp represent two matrix
The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.
But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.
The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:
![A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da11%26a12%5C%5Ca21%26a22%5Cend%7Barray%7D%5Cright%5D%5C%5CB%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11%26b12%5C%5Cb21%26b22%5Cend%7Barray%7D%5Cright%5D%5C%5CAB%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da11b11%2Ba12b21%26a11b12%2Ba12b22%5C%5Ca21b11%2Ba22b21%26a21b12%2Ba22b22%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CBA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11a11%2Bb12a21%26b11a12%2Bb12a22%5C%5Cb21a11%2Bb22ba21%26b21a12%2Bb22a22%5Cend%7Barray%7D%5Cright%5D)
Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.
Answer:
Step-by-step explanation:
For |x|=5, x can be either 5 or -5.
For |x|=-5, absolute value cannot be negative, so it is no solutions.