Answer:
Please see explanation below.
Explanation:
a. Cycle time = Production time available per hour / Units required per hour
= 60 / 5
= 12minutes
Minimum number of workstations = Sum of the task time / Cycle time
Sum of task time
= 8 + 10 + 8 + 10 + 8 + 4
= 48
The theoretical minimum number of work stations is
= 48 / 12
= 4
b. In order to assign the tasks to the work station, events that precede the task must be considered together with the time taken to complete each task.
°Task A This task is assigned to work station 1 and no task would further be assigned to work station 1, otherwise it will exceed the cycle time.
°Task B. This next task will be assigned to work station 2, no additional task will be assigned to station 2.
Task C is assigned to workstation 3, hence can no longer accept any other assigned task.
°Task D is the next task and will be assigned to work station 4, and we cannot assign any more task to work station 4.
°Task E and F will not be assigned as there are no more available stations.
Task Time Workstation
A. 8 1
B. 10 2
C. 8 3
D. 10 4
E. 8 -
F. 4 -
Please note that due to the theoretical minimum number of work station, which is 4, it will not be possible to assign task to all the workstations hence task E and F remains unassigned.
C. Efficiency of the assembly line
Efficiency ;
= Sum of task times / Actual number of work stations × cycle time
Although the actual number of required workstation is 5 but we cannot assign task E and F due to the theoretical minimum number of workstation. Therefore, additional work station will be required and there are 5 work stations in total.
= 48 ÷ (5 × 12) × 100
= 80%
