Question

Paulette has $140 in $5 and $10 bills. The number of $10 bills is one less than twice the number of $5 bills. How many of each does she have?
Provide your answer below

?=$ 10 bills ?=$5 bills

Answer 1

this needs a system

140=5x+10y

y= 2x-1

Now subsitute 2x-1 in for y

140=5x +10(2x-1)

140 = 25x -10

bring over the 10

150 = 25x

the divide

x = 6

now substitue x in in 2x-1

2(6) -1 = 11

there you have it, you have 6 five dollar bills and 11 ten dollar bills.

Answer 2

Answer:

11  $10 bills, 6 $5 bills

Step-by-step explanation:

10(2f−1)+5f=140

25f - 10=140

25f =150

f=6

So, there are 6 $5 bills. Since the number of $10 bills is  one less than twice the number of $5 bills, the number of $10 bills is        

2(6)−1=11.

Paulette has 11 $10 bills and 6 $5 bills.