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KengaRu [80]
2 years ago
13

A contracting company recently completed it's period of performance on a government contract and would like to destroy all infor

mation associated with contract performance Which of the following is the best NEXT step for the company to take?
A. Consult data disposition policies in the contract
B. Use a pulper or pulverizer for data destruction
C. Retain the data for a period of no more than one year.
D. Burn hard copies containing PII or PHI
Computers and Technology
1 answer:
Art [367]2 years ago
8 0

Answer: A. Consult data disposition policies in the contract

Explanation:

This is a Government Contract and as such may be subject to certain restrictions on how information should be handled or even destroyed.

The first thing the company should do therefore is to check the Data Disposition Policies that were included in the contract to see if and how they are to destroy the data and then proceed from there.

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You are a visitor at a political convention with delegates; each delegate is a member of exactly one political party. It is impo
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Answer:

The algorithm is as follows:

Step 1: Start

Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

Step 7: Else

Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

The next person on the list is set to index 1

Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

Step 6.1: If Parties[Individual] == Parties[I]:

Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

<em>Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n) </em>

Download txt
5 0
2 years ago
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