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djverab [1.8K]
3 years ago
7

You implement basic version control and go through the phase of creating a local repository. Initiate the commands to set up tha

t local repository
Computers and Technology
1 answer:
notsponge [240]3 years ago
3 0
Version control is the foundation of DevOps. Gain speed with Helix Core. Get the version control tools you need. Try today. Modern Collaboration. Increase Visibility.
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Where else can the computer send the results of processing other than to output​
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Explanation:

it can also be sent through flashdrive

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Each computer on a network requires a unique way to identify itself and to refer to other computers. This is accomplished by usi
pantera1 [17]

Answer:

True

Explanation:

<em>IP Address</em>: It is used to uniquely identify each device over the network.

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What is the function of a primary key in a table? to uniquely identify each record in the table to uniquely identify foreign key
aev [14]

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brainliest pls?

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What's a qat on a computer
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The answer is ..........

The Microsoft Quick Access Toolbar (QAT<span>) is a toolbar menu that appears in Microsoft Excel, Microsoft Word, and other Office 2007 and above products in the top left corner of the window. As seen in the picture, the Quick Access Toolbar gives you quick access to commonly used features such as the Save feature.
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3 years ago
Read 2 more answers
Computer system with a 32-bit logical address and 4k-byte page size. assume that each entry of a page table consists of 4bytes.
Annette [7]

The number of bits in the physical address is 26 bits. The number of entries in a page table is \mathbf{2^{20}} entries. The size of the page table in a one-level paging scheme is 4MB.

<h3>
What is paging in Operating System?</h3>

Paging is a storage method used in operating systems to recover activities as pages from secondary storage and place them in primary memory. The basic purpose of pagination is to separate each procedure into pages.

We are given the following parameters:

  • 32-bit logical address
  • Page size = 4 KB = \mathbf{2^{12} \ bytes }
  • Size of each Page table entry = 4 bytes

Suppose the system supports physical memory size = 64 MB = \mathbf{2^{26} \ bytes}

Thus, the number of bits in the physical address is computed as:

= \mathbf{log_2 \{Physical-memory-size\}}

=\mathbf{log_2(2^{26})}}

= 26 bits

The number of entries in a page table = logical address space size/page size

The number of entries in a page table \mathbf{= \dfrac{2^{32}}{2^{12}}}

\mathbf{=2^{20}} entries

In a one-level paging scheme, the size of the table is:

= entire no. of page entries × page table size

= \mathbf{2^{20}\times 4 \ bytes}

= 4 MB

b.

suppose that this system supports up to 2^30 bytes of physical memory.

  • The size of the page table will be the same as 4 MB due to the fact that the number of entries, as well as, the page table entry size is the same.

Since the size of the page table surpasses that of a single page. A page cannot include a whole page table. Therefore, the page table must be broken into parts to fit onto numerous pages, and an additional level of the page table is required to access this page table.

  • This is called the Multi-Level Paging system.

Therefore, we can conclude that the number of bits in the physical address is 26 bits, the number of entries in a page table is \mathbf{2^{20}} entries, and the size of the page table in a one-level paging scheme is 4MB.

Learn more about Paging in Operating System here:

brainly.com/question/17004314

#SPJ1

4 0
1 year ago
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