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djverab [1.8K]
2 years ago
7

You implement basic version control and go through the phase of creating a local repository. Initiate the commands to set up tha

t local repository
Computers and Technology
1 answer:
notsponge [240]2 years ago
3 0
Version control is the foundation of DevOps. Gain speed with Helix Core. Get the version control tools you need. Try today. Modern Collaboration. Increase Visibility.
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Which step in the software development life cycle involves making improvements based on user feedback?
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Answer:

Maintenance is the answer

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3 years ago
Does anybody know a better app I can use instead of Brainly
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3 years ago
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Write a function named countWords that reads in a line of text into a string variable, counts and returns the number of words in
algol13

Answer:

function countWords(sentence) {

return sentence.match(/\S+/g).length;

}

const sentence = 'This sentence  has five  words ';

console.log(`"${sentence}" has ${countWords(sentence)} words` );

Explanation:

Regular expressions are a powerful way to tackle this. One obvious cornercase is that multiple spaces could occur. The regex doesn't care.

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3 years ago
Which of the following is NOT a network configuration?
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It's definitely not ring or bus either mesh or Ethernet
4 0
2 years ago
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Suppose you wish to develop a matrix-multiplication algorithm that is asymptotically faster than Strassen’s algorithm. Your algo
Kazeer [188]

Answer:

The number of subproblems are given as T(n)=a*T(n/8)+\theta(n^2) while the value of T(n) to be less than S(n) is for 342.

Explanation:

The number of subproblems are given as

T(n)=a*T(n/8)+\theta(n^2)

Asymptotic running time for Strassen’s algorithm is S(n)=\theta(n^{log(7)})

Now, when a increases, number of subproblems determines the asymptotic running time of the problem and case 1 of master theorem applies. So, in worst case, asymptotic running time of the algorithm will be

T(n)=\theta(n^{logb(a)})=\theta(n^{log8(a)})=\theta(n^{log_{2}(a^{1/3})})

Now, for T(n) to be smaller than S(n)

n^{loga^{1/3}}

So,

log(a^{(1/3)})

So,

a=342

5 0
3 years ago
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