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vova2212 [387]
3 years ago
8

In a triangle abc, angle A=67 degrees and angle B=32 degrees. What is the measure of angle C?

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
8 0
67 + 32 =99
i think that angle c would be 81
jenyasd209 [6]3 years ago
3 0
The total degrees of a triangle is 180°

Therefore when you add angles A, B and C you should get the total of 180.

To find your missing angle you'll simply...

Add angle A and B.

67° + 32° = 99°

Then subtract your answer from 180°

180° - 99° = 81°

So the measure of your missing angle aka angle C is 81°
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VLD [36.1K]

Answer:

1/10

Step-by-step explanation:

2/5 a cup of sugar

1/2 a cup of flour

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8 0
2 years ago
Please help!! will mark branliest
Mashcka [7]

Answer:

a. After the first bounce, the ball will be at 85% of 8 ft. After 2 bounces, it'll be at 85% of 85% of 8 feet. After 3 bounces, it'll be at (85% of) (85% of) (85% of 8 feet).  You can see where this is going. After n bounces the ball will be at

h(n) = (85\%)^n 6ft = (\frac{17}{20})^n(6ft\times 12\frac{in}{ft}) = (\frac{17}{20})^n\times72'

b. After 8 bounces we can apply the previous formula with n = 8 to get

h(8)=(\frac{17}{20})^8\times 72' = 19.62'

c. The solution to this point requires using exponential and logarithm equations; a more basic way would be trial and error using the previous h(n)increasing the value of n until we find a good value. I recommend using a spreadsheet for that; the condition will lead to the following inequality:

1>(\frac{17}{20})^n\times 72 Let's first isolate the fraction by dividing by 72.

(\frac{17}{20})^n  Now, to get numbers we can plug in a calculator, let's take the natural logarithm of both sides:

ln ((\frac{17}{20})^n) < ln \frac 1{72} \rightarrow n\times ln (\frac{17}{20}) < -ln72. Now the two quantities are known - or easy to get with any calculator, replacing them and solving for n we get:

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3 years ago
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Answer:

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Step-by-step explanation:

Yes He was right. Place one atom in the centroid of the equilateral triangle (S or B), and each atom in each vertex(O or F).

We can apply geometric transformations (plane) rotations: R0, R2π/3, R4π/3

(And spatial ones, as R1, R2, R3 180º rotation over each median.)

Composite functions show that this is not an Abelian Group:

R_{1}\circ\:R_{2}=R_{\frac{2\pi}{3}}\\R_{2}\circ\:R_{1}=R_{\frac{4\pi}{3}}\\

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olchik [2.2K]

Answer:

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