It is asking you to find the sum of k^2 - 1 from k=1 to k=4. Since that is only 4 numbers, calculating the sum by hand wouldn’t be that bad.
(1^2 - 1) + (2^2 - 1) + (3^2 - 1) + (4^2 - 1) = 26
The easier way to find the sum is to use a few simple formulas.
When we have a term that is just a constant c, the formula is c*n.
When we have a variable k, the formula is k*n*(n+1)/2.
When we have a squared variable, the formula is k*n*(n+1)*(2n+1)/6.
In this case, we have a squared variable k^2 and a constant of -1.
So plug in n=4 to the formulas:
4*5*9/6 - 1*4 = 26
The answer is 26
The answer will be z=-6 because 16-8=6
For this case we have the following product:

We must use the distributive property correctly to solve the problem.
We have then:

Then, we must add similar terms.
We have then:
Answer:
The final product is given by:
option 2
767 rounded to the nearest ten is 770
Answer:
B
Step-by-step explanation:
The others involve opinions, not numbers
- Gage Millar, Algebra 2 tutor